If the sum of an integer and 7 more than the next consecutive integer is 66 then the integers are 29 and 30.
Given that the sum of an integer and 7 more than the next consecutive integer is 66.
Integer is a number that is written without a fraction component. It can be positive as well as negative.
let the first integer be x.
Consecutive integer will be x+1.
Sum of integer and 7 more than the next consecutive integer is 66.
Sum according to the given information=x+x+1+7
=2x+8
2x+8=66
2x=66-8
2x=58
x=58/2
x=29
Next integer=29+1-30.
Hence if the sum of an integer and 7 more than the next consecutive integer is 66 then the integers are 29 and 30.
Learn more about integers at brainly.com/question/17695139
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Answer:
1. 144 2. 16 3. 1 4. 3x-6
Step-by-step explanation:
So think of this as a function in a function. So you work from the inside to the outside. So for problem 1, we start with f(4)) [you read it "f of 4"] so what is the solution when x = 4, since f(x) means the function of x so f(4) means 'the function of 4' inside f(x).
Since f(x) = 3x then f(4) = 3(4) [notice how you substitute the 4 everywhere you see a letter x]
so f(4) = 12, now you work the next part h(f(4)) since f(4)=12 then h(12)
So take the h(x) function which is h(x) = 
then h(12) = 
so h(12) = 144
Answer:
A.
Step-by-step explanation:
The total amount Akash paid in those 3 months for his cell phone bill.
Answer:
t = -24*log(2/3)
Step-by-step explanation:
The expression is:
V = 22,500*10^(-t/12)
Replacing with V = 10,000 and isolating t, we get:
10,000 = 22,500*10^(-t/12)
10,000/22,500 = 10^(-t/12)
4/9 = 10^(-t/12)
(2/3)² = 10^(-t/12)
2*log(2/3) = -t/12
-12*2*log(2/3) = t
t = -24*log(2/3)
Answer:
158
Step-by-step explanation:
Simplify the following:
2×5×3 + 2×5×8 + 2×3×8
5×3 = 15:
2×15 + 2×5×8 + 2×3×8
5×8 = 40:
2×15 + 2×40 + 2×3×8
3×8 = 24:
2×15 + 2×40 + 2×24
2×15 = 30:
30 + 2×40 + 2×24
2×40 = 80:
30 + 80 + 2×24
2×24 = 48:
30 + 80 + 48
| 8 | 0
| 4 | 8
+ | 3 | 0
1 | 5 | 8:
Answer: 158
