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2 years ago

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A student scored 66 points on his Psychology 101 midterm. If the average of his midterm and final must be between 78 and 90 incl

usive for a B, then for what range of scores on the final exam would a student get a B? Both tests have a maximum of 100 points. Hint: Write a compound inequality with his average between 78 and 90 inclusive.

1 answer:

masha68 [24]2 years ago

5 0

Answer:

range of scores on final exam student get B is 90 to 100

Step-by-step explanation:

given data

Psychology 101 score = 66

average of his midterm = between 78 and 90

maximum = 100 points

to find out

range of scores on final exam student get B

solution

we consider here lowest marks need in final = x

so average at two marks should be

equation is

average marks = 0.5 × ( mid term marks + final marks ) .................1

put here value

78 = 0.5 × ( 66 + x )

x = 90

and

90 = 0.5 × ( 66 + x )

x = 114

so range 90 to 114

but maximum marks is 100 so

range of scores on final exam student get B is 90 to 100

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Step-by-step explanation:

Probability is the greater or lesser possibility that a certain event will occur. In other words, the probability establishes a relationship between the number of favorable events and the total number of possible events. Then, the probability of any event A is defined as the ratio between the number of favorable cases (number of cases in which event A may or may not occur) and the total number of possible cases. This is called Laplace's Law:

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Two events are dependent on each other when the fact that one of them is verified influences the probability of the other being verified. In other words, the probability of A happening is affected because B has happened or not.

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<em> It will be assumed first that the first ball drawn is black</em>. Then the probability of this happening is $\frac{10}{15}$ since the number of black balls in the urn is 10 and the total number of cases is 15. It is now known that the second ball extracted will be white. Then the number of favorable cases will be 5 (number of white balls inside the ballot urn), but now the number of total cases is 14, because a ball was previously removed that was not replaced. So the probability of this happening is $\frac{5}{14}$

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These are events are incompatible, since I cannot, in a first extraction, extract a black and white ball at the same time. So:

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