Answer:
28.6, that is, about 29 are expected to be defective
Step-by-step explanation:
For each battery, there are only two possible outcomes. Either it is defective, or it is not. The probability of a battery being defective is independent of other betteries. So the binomial probability distribution is used to solve this question.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
The expected value of the binomial distribution is:

The probability that a battery is defective is 1/14.
This means that 
400 batteries.
This means that 
How many are expected to be defective?

28.6, that is, about 29 are expected to be defective
Answer:
k = -3
Step-by-step explanation:
log7(-5k - 3) = log7 (-4k)
---> -5k - 3 = -4k
-k - 3 = 0
k = -3
Answer:
A
Step-by-step explanation:
The 7 is in the hundredths place.
Answer:
look above
Step-by-step explanation:
hope it hepls