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mina [271]
2 years ago
14

Please help me in this one!!

Mathematics
2 answers:
olga2289 [7]2 years ago
6 0
A^3
a to the power of three
Nostrana [21]2 years ago
6 0
A^3, or a to the power of 3
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Help me figure out what X is
11Alexandr11 [23.1K]

8x+11=7x+26\\ 8x-7x=26-11\\ x=15

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3 years ago
Can someone help me answer this question ( moderators this is not a copy, the other ones got erased so go away)
Rainbow [258]
Triangles ABC and ADE are similar triangles. That means the sides are all scaled by the same factor.

To go from side BC to side DE, you multiply by 1.25. That means 1.25 is your scale factor. Now apply that factor to the bottom side to get your answer.

Side AB is 6. That means side AD is 6 x 1.25 = 7.5. That means x = 7.5 - 6 = 1.5
6 0
3 years ago
Dan bought one package if blackberries for 3 dollars/euros. How many packages can Darryl buy if he has 15 dollars/euros?​
myrzilka [38]

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Dan can buy 5 bags for 15 dollars

Step-by-step explanation:

divide 15 and 3 it will equal 5

6 0
2 years ago
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What are all of the Angle measures
Semmy [17]

Answer:Type of Angle Description

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Straight Angle is 180° exactly

Step-by-step explanation:

5 0
3 years ago
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Which expression is equivalent
gtnhenbr [62]

Answer:

Option  B is correct.

\frac{81m^2n^5}{8} is equivalent to \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}

Step-by-step explanation:

Given expression: \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}

Using exponents power:

  • (ab)^n = a^nb^n
  • (a^n)^m = a^{nm}
  • a^m \cdot a^n = a^{m+n}

Given: \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}

Apply exponent power :

⇒ \frac{3^4 (m^{-1})^4(n^2)^4}{2^3(m^{-2})^3 n^3}

⇒ \frac{81 m^{-4}n^8}{8m^{-6}n^3} = \frac{81 m^{-4} \cdot m^6 n^8 \cdot n^{-3}}{8}

⇒\frac{81 m^{-4+6} n^{8-3}}{8} = \frac{81 m^2 n^5}{8} = \frac{81m^2 n^5}{8}

Therefore, the expression which is equivalent to  \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3} is,  \frac{81m^2 n^5}{8}

4 0
3 years ago
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