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mina [271]
2 years ago
14

Please help me in this one!!

Mathematics
2 answers:
olga2289 [7]2 years ago
6 0
A^3
a to the power of three
Nostrana [21]2 years ago
6 0
A^3, or a to the power of 3
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USPshnik [31]

Answer:

{x}^{3}  +  13 {x}^{2}   + 34x  - 56

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(x + 7)( {x}^{2}  + 6x - 8) \\  = x ( {x}^{2}  + 6x - 8)  +  7( {x}^{2}  + 6x - 8)  \\  =  {x}^{3}  + 6 {x}^{2}  - 8x + 7 {x}^{2}  + 42x - 56 \\  = {x}^{3}  +  6 {x}^{2}  + 7 {x}^{2} + 42x - 8x - 56 \\  = {x}^{3}  +  13 {x}^{2}   + 34x  - 56 \\

6 0
3 years ago
Read 2 more answers
Hi can someone please answer my question. thank you ❤️​
Ne4ueva [31]
Hope this helps, have a great!!

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2 years ago
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