The common ratio is: $\mathbf{r = \frac{a + 5d}{a + d}}$
The general term of the GP is: $\mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}$

The nth term of an AP is:

$\mathbf{T_n = a + (n - 1)d}$

So, the 2nd, 6th and 8th terms of the AP are:

$\mathbf{T_2 = a + d}$

$\mathbf{T_6 = a + 5d}$

$\mathbf{T_8 = a + 7d}$

The first, second and third terms of the GP would be:

$\mathbf{a_1 = a + d}$

$\mathbf{a_2 = a + 5d}$

$\mathbf{a_3 = a + 7d}$

The common ratio (r) is calculated as:

$\mathbf{r = \frac{a_2}{a_1}}$

This gives

$\mathbf{r = \frac{a + 5d}{a + d}}$

The nth term of a GP is calculated using:

$\mathbf{a_n = a_1r^{n-1}}$

So, we have:

$\mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}$

Read more about arithmetic and geometric progressions at:

brainly.com/question/3927222

6 0

3 years ago

What is the value of z in the equation 2(4z − 9 − 7) = 166 − 46?

kumpel [21]

Hi there!

2(4z - 9 - 7) = 166 - 46
let's make this a little more simpler...

2(4z - 16) = 120

use distributive property.
multiply 2 and 4z , 2 and -16.
8z - 32 = 120

add 32 on both sides to isolate the variable

8z = 152

divide both sides by 8...

z = 19

So your answer is A. 19

Hope this helped!! :)

8 0

3 years ago

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