Slope intercept form: y = mx + b
mx = slope
b = y-intercept
We know the y intercept is 0, so nothing will be written there.
To find the slope of this line, we can use the slope formula.
We'll use the points (1, 0) and (3, 1) to find the slope.
Now we can just plug these values into the equation to find the slope.
1 - 0 / 3 - 1
1 / 2
The slope of the line is 1/2, or 0.5.
The slope-intercept form of this line can be written as:
y = 0.5x
A) multiply equation A by -2 so you get -2x - 2z = -12 and then you can add both equations to eliminate z
(0,5)(3,-1)
slope = (-1 - 5) / (3 - 0) = -6/3 = -2
y = mx + b
slope(m) = -2
(use either of ur points...(0,5)...x = 0 and y = 5
now we sub and find b, the y int
5 = -2(0) + b
5 = b
so ur line is : y = -2x + 5
14/4 > 1 is what it looks like.
2(x-5)=20
Divide both sides by 2 (division of property equality)
x - 5 = 10
Add 5 to both sides (addition of property equality)
x = 15
Answer
x = 15 is the solution
