To Find :
How many gallons of a 80% antifreeze solution must be mixed with 100 gallons of 20% antifreeze to get a mixture that is 70% antifreeze.
Solution :
Let, x gallons of 80% antifreeze solution is required :
So,
Therefore, 500 gallons of 80% antifreeze solution is required.
Answer:
x=-2;y=-7
Step-by-step explanation:
y=5x+3
y=3x-1
3x-1=5x+3
-2x=4
x=-2 y=5x+3 y=5×(-2)+3 y=-7
Answer:
it 1/3
Step-by-step explanation:
2/4 is just 1/2, 3/6 is also 1/2, 7/9 is over 1/2 and 1/3 is the only one less then 1/2 so it's the lowest fraction. This is not the proper way to solve it but it works and it's faster
Answer:
c
Step-by-step explanation:
