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postnew [5]
2 years ago
15

1. is the expression

ss="latex-formula"> equivalent to (8x8)^5
2. is the expression (3^2)^3 equivalent to (3^3)^2

3. is the expression \frac{3^2}{3^3} equivalent to \frac{3^3}{3^2}

explain for all.
Mathematics
2 answers:
Morgarella [4.7K]2 years ago
5 0
No, in because of the parentheses, the 5 has to be distributed to all of the variables in the equation.
Lady_Fox [76]2 years ago
4 0

Answer:

No

Step-by-step explanation:

No, because 8x8^58x85 only takes the 8 that it is up against to the fifth power, but (8x8)^5(8x8)5 takes the whole expression to the fifth power.

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tigry1 [53]

16

Place in ascending order: 4 6 8 15 15 17 17 18 20 20

middle numbers = 15 and 17

(15+17)/2 = 16

4 0
2 years ago
What must you do to the first inequality to get to the second inequality? A. N 4 <5;n<20 b. − n 4 <5;n>−20 A. A. Add
adell [148]

A. You have two inequalities:

  • \dfrac{n}{4}
  • n

If you multiply the first inequality by positive number 4 (multiplying inequality by positive number doesn't change the inequality sign), then you get the inequality

4\cdot \dfrac{n}{4}

B. You have two inequalities:

  • -\dfrac{n}{4}
  • n>-20.

If you multiply the first inequality by negative number -4 (multiplying inequality by negative number changes the inequality sign), then you get the inequality

-4\cdot \left(-\dfrac{n}{4}\right)>-4\cdot 5,\\ \\n>-20.

Answer: option D.

5 0
3 years ago
Simplify the expression below.
olasank [31]
\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{  n}}}\implies \cfrac{1}{a^{-{{  n}}}}
\\\\
-------------------------------\\\\

\bf \cfrac{14a^8y^3-7a^4y^5+28a^{12}y^2}{7a^4y}\impliedby 
\begin{array}{llll}
\textit{let us first, distribute}\\
the~denominator
\end{array}
\\\\\\
\cfrac{14a^8y^3}{7a^4y}-\cfrac{7a^4y^5}{7a^4y}+\cfrac{28a^{12}y^2}{7a^4y}
\\\\\\
\cfrac{14}{7}a^8a^{-4}y^{-1} y^3-\cfrac{7}{7}a^4a^{-4}y^{-1} y^5+\cfrac{28}{7}a^{12}a^{-4}y^{-1} y^2
\\\\\\
2a^{8-4}y^{-1+3}-1a^{4-4}y^{-1+5}+4a^{12-4}y^{-1+2}
\\\\\\
2a^4y^2-1\cdot 1y^4+4a^8y\implies 2a^4y^2-y^4+4a^8y
4 0
2 years ago
What is the actual area, in square meters, of this field?
o-na [289]

Answer:

Step-by-step explanation:

First it base times height times (1/2)

The base is 7 boxes

The height is 5 boxes

A=(7)(5)(1/2)

A=(35)(1/2)

A=17.5

8 0
2 years ago
Read 2 more answers
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solniwko [45]
To find 86% of 50, you do 50*.86 (because .86 is the decimal form of the percentage 86%)

50*.86=43 people

Hope this helps
8 0
3 years ago
Read 2 more answers
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