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Delicious77 [7]
3 years ago
12

Dixon and his little sister Ariadne stand next to each other on the playground on a sunny afternoon. Their mother measures their

shadows. Dixon's shadow is 18 feet long and Ariadne's shadow is 15 feet long. If Dixon is 6 feet tall, how tall is Ariadne?
Mathematics
2 answers:
MAVERICK [17]3 years ago
4 0
Ariadne is 5 feet tall because 18 is 6x3 which would mean you would have to divide 15 by three to get the answer which is 5.
mash [69]3 years ago
3 0
She would be 5ft tall because if you set the problem up in a ratio and cross multiple and divide 5 is your answer

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En una ciudad se registró una temperatura de 12°c bajo cero a las 3:00 am si a las 7:00am del mismo dia la temperatura era tres
hjlf

Answer:

24°c

Step-by-step explanation:

Cuando se dice que la temperatura esta "mayor" significaria que esta aumentando y entorno subiendo a ser mas caliente. Siendo este el caso, si la temperatura a las 3:00 estaba a 12c bajo cero entonces a las 7:00 estaria a 24c. Esto es por que un aumento de tres vecesseria un aumento de 36 grados (12*3). 12c grados bajo cero seria un numero negativo y si sumamos estos numeros nos daria 24c grados.

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Step-by-step explanation:

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Answer:  \bold{(1)\ \dfrac{19,683}{64}\qquad (2)\ 16}

<u>Step-by-step explanation:</u>

(1)           (12, 18, 27, ...)

The common ratio is:

r=\dfrac{a_{n+1}}{a_n}\quad r =\dfrac{18}{12}=\boxed{\dfrac{3}{2}}\quad \rightarrow \quad r=\dfrac{27}{18}=\boxed{\dfrac{3}{2}}

The equation is:

a_n=a_o(r)^{n-1}\\\\Given:a_o=12,\  r=\dfrac{3}{2}\\\\\\Equation:\\a_n =12\bigg(\dfrac{3}{2}\bigg)^{n-1}\\\\\\\\9th\ term:\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{9-1}\\\\\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{8}\\\\\\.\quad =\large\boxed{\dfrac{19643}{64}}

(2)\qquad \bigg(\dfrac{1}{16},\dfrac{1}{8},\dfrac{1}{4},\dfrac{1}{2}\bigg)\\\\\\\text{The common ratio is}:\\\\r=\dfrac{a_{n+1}}{a_n}\quad  r=\dfrac{\frac{1}{8}}{\frac{1}{16}}=\boxed{2}\quad \rightarrow \quad r=\dfrac{\frac{1}{4}}{\frac{1}{8}}=\boxed{2}

The equation is:

a_n=a_o(r)^{n-1}\\\\Given:a_o=\dfrac{1}{16},\  r=2\\\\\\Equation:\\a_n =\dfrac{1}{16}(2)^{n-1}\\\\\\\\9th\ term:\\a_9=\dfrac{1}{16}(2)^{9-1}\\\\\\a_9=\dfrac{1}{16}(2)^{8}\\\\\\.\quad =\large\boxed{16}

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