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3 years ago

5

Babe ruth has a lifetime batting average of 0.342. assume that babe ruth came to bat officially six times every game played. wha

t would be babe ruth's probability getting at least five hits in a game?

1 answer:

topjm [15]3 years ago

5 0

Hello there

the answer is 0.658

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The selling price for houses in a neighborhood in West Richland, WA have an approximately normal distribution with a mean sellin

Liula [17]

The probability that the average selling price of the 35 homes will be within $2000 of the true mean is 0.5753

First, we need to find the z-score and this is expressed according to the formula;

$z=\dfrac{x-\mu}{\sigma}$

x is the sample space

$\mu$ is the mean value

$\sigma$ is the standard deviation

Given the following parameters

Mean = $275,000

Standard deviation = $10,500

If the true mean is $273,000, then;

$z=\dfrac{273,000-275000}{10,500} \\z = \frac{-2000}{10500}\\z= -0.1905$

If the true mean is $277,000

$z=\dfrac{277,000-275000}{10,500} \\z = \frac{2000}{10500}\\z= 0.1905$

This means that the z-score is between -0.1095 and 0.1095

Pr( -0.1095 ≤ z ≤ 0.1095)

According to the z table, the probability that the average selling price of the 35 homes will be within $2000 of the true mean is 0.5753

Learn more here: brainly.com/question/17436641

3 0

2 years ago

Helen is putting a fence around her flower garden, which is in the shape of half of a circle and a rectangle. If the semicircle

erastova [34]

Answer:

Part 1) Helen will need 38 feet of fencing

Part 2) The perimeter around the three sides of the rectangular section of the garden is 27 feet

Part 3) The approximate distance around half of the circle is 11 feet

Step-by-step explanation:

Part 1) How much fencing will Helen need?

Find out the perimeter

we know that

The perimeter of the figure is equal to the sum of three sides of the rectangular section plus the circumference of a semicircle

so

$P=2L+W+\frac{1}{2}\pi D$

we have

$L=10\ ft\\W=7\ ft\\D=7\ ft\\\pi =\frac{22}{7}$

substitute

$P=2(10)+7+\frac{1}{2}(\frac{22}{7})(7)$

$P=20)+7+11=38\ ft$

therefore

Helen will need 38 feet of fencing

Part 2) What is the perimeter around the three sides of the rectangular section of the garden?

$P=2L+W$

we have

$L=10\ ft\\W=7\ ft$

substitute

$P=2(10)+7$

$P=20+7=27\ ft$

therefore

The perimeter around the three sides of the rectangular section of the garden is 27 feet

Part 3) What is the approximate distance around half of the circle?

Find the circumference of semicircle

$C=\frac{1}{2}\pi D$

we have

$D=7\ ft\\\pi =\frac{22}{7}$

substitute

$C=\frac{1}{2}(\frac{22}{7})(7)$

$C=11\ ft$

therefore

The approximate distance around half of the circle is 11 feet

4 0

2 years ago

Read 2 more answers

If John read only 10 pages of a book in an hour, how long would it take to read all the pages of the book if it has 487 pages?

melisa1 [442]

Forty nine hours and ten minutes I’m pretty sure

4 0

2 years ago

Someone please help meee

zzz [600]

B = -16
m = (-15-(-16))/18-0 = 1/18
y= 1/18x - 16

6 0

3 years ago

Help me with this problem please!!!!

Ira Lisetskai [31]

Step-by-step explanation:

sorry I wanted to help you but my calculator is take out decimals sorry I don't know what to do

4 0

3 years ago