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anygoal [31]
3 years ago
12

Tegan bought 1 1/6 metres of ribbon. She needs 2/5 metres to wrap her brothers present and 3/4 metres to wrap her sisters presen

t. Did she buy enough ribbon?
Mathematics
1 answer:
fgiga [73]3 years ago
6 0

Answer:

Yes

Step-by-step explanation:

2/5 + 3/4 = [2(4) + 3(5)]/20

= 23/20 = 1 3/20

1 3/20 = 1 9/60

1 1/6 = 1 10/60

1 1/6 > 1 3/20

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What<br> Is the volume of this object
ad-work [718]

Answer:

100

Step-by-step explanation:

5x4=20

20x5=100

8 0
3 years ago
Read 2 more answers
Park Rangers at the North Rim of the Grand Canyon recorded the amounts of rainfall over 12 months. What was the total amount of
myrzilka [38]

Answer:

65.532cm of rainfall over 12 months

Step-by-step explanation

5 0
3 years ago
It's geometry please help.
oksano4ka [1.4K]

Answer:

BC = 22

Step-by-step explanation:

BD = 67

Bc = 3x - 2

CD = 4x + 13

BC + CD = BD (Given)

3x - 2 + 4x + 13 = 67

3x + 4x -2 + 13 = 67

7x + 11 = 67

7x = 67 - 11

7x = 56

x = 56 ÷ 7

x = 8

now instead of x put 8

Bc = 3x - 2

BC = 3(8) -2

BC = 24 -2

BC = 22

4 0
3 years ago
A particular sale involves four items randomly selected from a large lot that is known to contain 9% defectives. Let X denote th
umka2103 [35]

Answer:

The expected repair cost is $3.73.

Step-by-step explanation:

The random variable <em>X</em> is defined as the number of defectives among the 4 items sold.

The probability of a large lot of items containing defectives is, <em>p</em> = 0.09.

An item is defective irrespective of the others.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 9 and <em>p</em> = 0.09.

The repair cost of the item is given by:

C=3X^{2}+X+2

Compute the expected cost of repair as follows:

E(C)=E(3X^{2}+X+2)

        =3E(X^{2})+E(X)+2

Compute the expected value of <em>X</em> as follows:

E(X)=np

         =4\times 0.09\\=0.36

The expected value of <em>X</em> is 0.36.

Compute the variance of <em>X</em> as follows:

V(X)=np(1-p)

         =4\times 0.09\times 0.91\\=0.3276\\

The variance of <em>X</em> is 0.3276.

The variance can also be computed using the formula:

V(X)=E(Y^{2})-(E(Y))^{2}

Then the formula of E(Y^{2}) is:

E(Y^{2})=V(X)+(E(Y))^{2}

Compute the value of E(Y^{2}) as follows:

E(Y^{2})=V(X)+(E(Y))^{2}

          =0.3276+(0.36)^{2}\\=0.4572

The expected repair cost is:

E(C)=3E(X^{2})+E(X)+2

         =(3\times 0.4572)+0.36+2\\=3.7316\\\approx 3.73

Thus, the expected repair cost is $3.73.

4 0
3 years ago
The cost of renting a bicycle from Dan's Bike Shop is $2 for 1 hour plus $1 for each additional hour of rental time. Which of th
Vlad [161]

option B

Explanation:

The cost of renting per hour = $2

For 1 hour = $2

For each additional hour, it is $1

For 2 hours = First hour + 1(additional hour)

For 2 hours = $2 + $1(1) = 2+1 = $3

For 3 hours = $2 + $1 (2) = 2+2 = $4

For 4 hours = $2 + $1(3) = 2+3 = $5

The graph which shows this rental cost as 2, 3, 4, 5 is option B

7 0
1 year ago
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