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anygoal [31]
4 years ago
12

Tegan bought 1 1/6 metres of ribbon. She needs 2/5 metres to wrap her brothers present and 3/4 metres to wrap her sisters presen

t. Did she buy enough ribbon?
Mathematics
1 answer:
fgiga [73]4 years ago
6 0

Answer:

Yes

Step-by-step explanation:

2/5 + 3/4 = [2(4) + 3(5)]/20

= 23/20 = 1 3/20

1 3/20 = 1 9/60

1 1/6 = 1 10/60

1 1/6 > 1 3/20

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In the figure below, the segment is parallel to one side of the triangle. The ratio of 12 to y is 1:2 1:3 1:4 2:3
Brrunno [24]

Answer:

Option B. 1 : 3

Step-by-step explanation:

There are two triangles shown in the picture attached ΔABC and ΔCD.

In these triangles sides AB and DE are parallel and BC is transverse line so ∠ABC = ∠EDC (corresponding angles)

Similarly AC is transverse to parallel lines AB and DE, so ∠BAC = ∠DEC (corresponding angles)

∠ACB is common in both the triangles.

Therefore ΔABC and ΔDEC are similar.

We know in similar triangles corresponding sides are in the same ratio.

\frac{AB}{ED}=\frac{AC}{EC}

\frac{y}{12}=\frac{30+15}{15}=\frac{45}{15}=3:1

Therefore ratio of y and 12 is equal to 3 : 1

Or ratio of 12 to y is 1 : 3

Option B is the answer.

7 0
4 years ago
Read 2 more answers
Find the slope of (-19,-6),(15,16)
hram777 [196]

Answer:

0.647

Step-by-step explanation:

this is also known as gradient of the line

4 0
3 years ago
Help me with this problem
ryzh [129]

Answer:

angle 1 = angle 3

= 180°-136°

=44°

= angle 3

3 0
3 years ago
A deck of 52 cards is shuffled. The first five cards of the deck are red. What is the probability that the last card in the deck
saveliy_v [14]

Answer:

The answer is "\frac{1}{47}".

Step-by-step explanation:

Although the five first players are red, the very first five cards are not spaded as the spad is a black card.  

Its chance of the final card mostly on deck being the ace of spades is therefore determined as:

= \frac{1}{\text{Number of remaining cards with the initial 5 cards}} \\\\= \frac{1}{47}

Thus, \frac{1}{47} here is the necessary chance.

7 0
3 years ago
given a rectangle that is 21 cm longer than it is wide. Express the perimeter (in cm) of a rectangle in terms of its width w.
pashok25 [27]
L = W + 21

P = 2(L + W)
P = 2(W + 21 + W)
P = 2(2W + 21)
P = 4W + 42

answer
P = 4W + 42 (cm)
6 0
3 years ago
Read 2 more answers
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