if say we have a widht of w, and its length is <u>4 times as long as </u><u>w</u>, then its length is 4*w or 4w.
![\bf \textit{area of a rectangle}\\\\ A=Lw~~ \begin{cases} L=4w\\ A=16 \end{cases}\implies 16=(4w)w\implies 16=4w^2 \\\\\\ \cfrac{16}{4}=w^2\implies 4=w^2\implies \sqrt{4}=w\implies \boxed{2=w} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{perimeter}{\stackrel{L}{4(2)}+\stackrel{w}{2}\implies 10}\hfill](https://tex.z-dn.net/?f=%20%5Cbf%20%5Ctextit%7Barea%20of%20a%20rectangle%7D%5C%5C%5C%5C%20A%3DLw~~%20%5Cbegin%7Bcases%7D%20L%3D4w%5C%5C%20A%3D16%20%5Cend%7Bcases%7D%5Cimplies%2016%3D%284w%29w%5Cimplies%2016%3D4w%5E2%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B16%7D%7B4%7D%3Dw%5E2%5Cimplies%204%3Dw%5E2%5Cimplies%20%5Csqrt%7B4%7D%3Dw%5Cimplies%20%5Cboxed%7B2%3Dw%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%20%5Cstackrel%7Bperimeter%7D%7B%5Cstackrel%7BL%7D%7B4%282%29%7D%2B%5Cstackrel%7Bw%7D%7B2%7D%5Cimplies%2010%7D%5Chfill%20)
Answer:
22.5%
Step-by-step explanation:
72 divide by 120=
22.5%
Answer:
- -3 + 5
- 2
Step-by-step explanation:
- When you subtract a negative, the two signs (-) cancel out to form a positive sign (+). So, -3 - (-5) = -3 + 5
- -3 + 5 = 2
I hope this helps!