V = a²h/3
Plugging values in we get 8.67X10^7, or 86,700,000
2b^2 + 81/2 b + 4
basically 2b^2 + 16b + 49/2 b + 4
= (2b^2) + 16b+49/2b) + (4)
= 2b^2 + 81/2 b + 4
1. y₁ = 70x
2. y₂ = 55x
Solve y₁ - y₂ for x = 11.
Answer:
1,500 Kg
Step-by-step explanation:
Formual for froce is given by
force = mass * acceleration
Force exerted by 1 woman = 425 N
no. of women exerting force = 3
Force exerted by 3 woman = 425 * 3 N = 1275 N
Acceleration produced by 1275 N force = 0.85 m/s^2
Using formula force = mass * acceleration
1275 = mass * 0.85 m/s^2
=> mass = 1275/ 0.85 m/s^2 = 1,500 Kg
Thus, mass of car is 1,500 Kg.
The origin is just (0,0) and we can multiply that slope, -4/3 by any number to get the second point. let's use x=3 to make is simple as possible, the second point is then just (3,-4)
Connect (0,0) to (3,-4) and you have your line :)