Answer:
Th answer is: Marginal tax rate for Family A is 20%, average tax rate is 12%. There is no Family B in the question.
Explanation:
Family A's tax rate are as follows:
Income Tax rate
up to $10,000 0%
$10,000 to $30,000 10%
$30,000 to $50,000 20%
$50,000 to $80,000 30%
over $80,000 40%
Since Family A's income is $50,000, their marginal tax rate is 20%, and its average tax rate is = [($20,000 x 10%) + ($20,000 x 20%) / $50,000] = ($2,000 + $4,000) / $50,000 = $6,000 / $50,000 = 12%
They don't. Water was found and there are actually implications that if it doesn't exist nowadays, it might have historically existed long before there was even life on earth. There are theories that there was life on Mars millions of years ago way before earth had life.
Answer:
C. $3,857
Explanation:
Calculation for How much bonus will Robin receive as a result of this transaction
First step is to calculate the bonus amount
Bonus amount=75,000-66,000
Bonus amount=9,000
Second Step is to calculate the Amount received by Robin
Amount received by Robin=9,000*3/(4+3)
Amount received by Robin=9,000*3/7
Amount received by Robin=$3,857
Therefore the amount of bonus that Robin
will receive as a result of this transaction will be $3,857
Answer:
WB = BA(WA) + BB(WB) + BC (WC) + BD(WD)
1.6 = 0.83(0.5) + 1.50(0.1) + 1.42(0.15) + BD(0.25)
1.6 = 0.415 + 0.15 + 0.213 + 0.25BD
1.6 = 0.778 + 0.25BD
1.6-0.778 = 0.25BD
0.822 = 0.25BD
BD = 0.822/0.25
BD = 3.288
Explanation: The question relates to Beta of a portfolio. The Beta of a portfolio is the aggregate of Beta of each stock multiplied by the weight of each stock. The Beta of stock D was not given, thus, it becomes the subject of the formula.
Answer:
<h2>Assembly Line</h2>
1. Probability that a unit ends up in rework = Probability of defect in 20 stations multiplied by the probability of catching defects = 0.8%(1% x 80%) = 0.008
2. Probability that a defective unit is shipped = Probability of defective units during inspection plus Probability of defective units during rework = 25% (20% + (100-95%)) = 0.25
Explanation:
a) Probability of defect in 20 stations = 0.5% x 20 = 1%. Each station has a 0.05%
b) Probability of defective units during inspection = 20% (100% - 80)
c) Probability of defective units during rework = 5% (100% -95)
c) Probability is the likelihood or chance of an event occurring. Divide the number of events by the number of possible outcomes. This will give us the probability of a single event occurring.
