container that holds 0.152mol of xenon gas has a volume of 3.41L. What will the volume be if an additional 0.190mol of xenon is
added to the container and the temperature and pressure are kept constant?
1 answer:
Answer:
V₂ = 7.7 L
Explanation:
Given data:
Initial moles = 0.152 mol
Initial volume = 3.41 L
Final volume = ?
Final moles = 0.152 + 0.190 = 0.342 mol
Solution:
According to Avogadro law,
V₁/n₁ = V₂/n₂
V₂ = V₁n₂/n₁
V₂ = 3.41 L × 0.342 mol / 0.152 mol
V₂ = 1.17 L. mol/ 0.152 mol
V₂ = 7.7 L
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