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puteri [66]
3 years ago
9

Which is the angle measure represented by 7.5 rotations clockwise?

Mathematics
2 answers:
horrorfan [7]3 years ago
7 0

Answer:

-2700°


Step-by-step explanation:

  • 1 rotation is 360°, also
  • Counterclockwise angles are POSITIVE ANGLES & Clockwise angles are NEGATIVE ANGLES

7.5 rotations is 360*7.5=2700 degrees

and since it is clockwise, the angle is negative.


Hence, 7.5 rotations clockwise means -2700°

Mars2501 [29]3 years ago
5 0
1 rotation equals 360 degrees.  1/2 of a rotation equals 360/2 = 180 degrees.  So, 7 times 360 degrees = 2520 degrees plus 180 degrees = 2700 degrees.
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The drawing is a scale drawing of a house.
Alborosie

Answer: 20.25ft

1. Find what 8 inches in scale equal for the height of the house.

we will do this step by multiplying.

2in=4.5

8=?

to find...

2x4=8

so

4.5x4=18

2. Find what 1 inch on the scale is equal to for the height of the house.

we will do this by dividing 4.5 by 2

4.5/2=2.25

3. Add both the values for step 1 and 2.

we will do this by just adding them both

18+2.25=20.25

<h2>Why is this our answer?</h2>

This is our answer, because first we found the value of 8 inches on the scale, which means that we are finding almost the full value of the 9 inches of the height of the house, then, we found 1 inch because 9-8=1, so if we already found 8, which is a number in the table of 2, we found out 1 so that we can add it with 8 to find the value of 9in on the scale. In this way, after adding, that gives us the value of 9in on the scale!

My gratitude attitude - THANKS!

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2 years ago
X2 - 6x + 12 and y = 2x - 4, algebraically are
olga_2 [115]

<em><u>The solution is (4, 4)</u></em>

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

y = x^2 - 6x + 12 ------ eqn\ 1\\\\y = 2x - 4 ---------- eqn\ 2

<em><u>Substitute eqn 2 in eqn 1</u></em>

x^2 - 6x + 12 = 2x - 4

Make the right side of equation 0

x^2 - 6x + 12 - 2x + 4 = 0\\\\x^2 -8x + 16 = 0

<em><u>Solve by quadratic equation</u></em>

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=-8,\:c=16:\\\\x=\frac{-\left(-8\right)\pm \sqrt{\left(-8\right)^2-4\cdot \:1\cdot \:16}}{2\cdot \:1}\\\\x=\frac{-\left(-8\right)\pm \sqrt{0}}{2\cdot \:1}\\\\x = \frac{8}{2}\\\\x = 4

<em><u>Substitute x = 4 in eqn 2</u></em>

y = 2(4) - 4

y = 8 - 4

y = 4

Thus solution is (4, 4)

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