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jenyasd209 [6]
3 years ago
14

What is the radius for the circle given by the equation? 

Mathematics
1 answer:
alisha [4.7K]3 years ago
7 0

Use:

(a-b)^2=a^2-2ab+b^2\qquad(*)

x^2+y^2-6y-12=0\ \ \ \ |+12\\\\x^2+y^2-6y=12\\\\x^2+y^2-2y\cdot3=12\ \ \ \ |+3^2\\\\x^2+\underbrace{y^2-2\cdot y\cdot3+3^2}_{(*)}=12+3^2\\\\x^2+(y-3)^2=21\\\\\boxed{k=3}

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Domino's offers the following “deals”:
tia_tia [17]

Answer: Deal one: 5x+10

Deal two: 6x

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3 years ago
Which of the following equations has the same solutions as the equation 3x + 2y= -12
tatuchka [14]

Answer:

x= -2/3y-4

Step-by-step explanation:

3x+2y=-12

3x+2y-2y= -2y-12

3x=-2y-12

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x= -2/3y-4

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A worm travels 1250 millimeters how many meters did the worm travel
nataly862011 [7]
The worm traveled 1.25 meters
6 0
3 years ago
Read 2 more answers
2) In 1000 sq. meter of land a farmer cultivated 765 kg of rice with the wastage of 23.5%. I) Find the weight of the wastage. II
LiRa [457]

Answer:

Weight of wastage=179.775kg

weight of rice cultivated= 585.225 kg

percentage of rice cultivated=76.5%

Step-by-step explanation:

Area of land=100 square meters

Cultivated rice=765kg

Wastage=23.5%

1) Weight of the wastage=23.5% of 765kg

=23.5/100 × 765

=17977.5 / 100

=179.775 kg

2) Weight and percentage of rice cultivated.

weight of rice cultivated = 765 kg - 179. 775 kg

= 585.225 kg

percentage of rice cultivated = 100 - 23.5

= 76.5%

3) if area is increased 40 times in size

New area=1000 square meters × 40

=40,000 square meters

Cultivated rice= 765kg × 40

=30,600 kg

Cultivated rice excluding wastage=585.225 kg × 40

=23,409 kg

8 0
3 years ago
During a scuba dive, Lainey descended to a point 29 feet below the ocean surface. She continued her descent at a rate of 29 feet
Alex73 [517]

Answer:

Her initial position was:

-29ft

Where we use the minus sign because this is below the ocean's surface.

Now we also know that she keeps descending at a rate of -29ft per minute, then if she keeps descending for t minutes, her position will be:

P(x) = -29ft - 29ft/min*t

Now, we also know that she does not want to descend more than 81ft below the ocean's surface, then we have the inequality:

P(x) ≥ -81ft

-29ft - 29ft/min*t ≥ -81ft

Now let's isolate t in one side:

- 29ft/min*t ≥ -81ft + 29ft = -52 ft

- 29ft/min*t ≥-52 ft

                t ≤ -52ft/(- 29ft/min) = 1.79 min

Then the maximum amount of time that she can keep descending is 1.79 minutes.

6 0
3 years ago
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