Answer:
The simplified expressions are (<em>x</em> + <em>y·</em>z' + <em>t</em>) and <em>x·</em>(<em>x</em> + <em>y</em>' + <em>z</em>) respectively.
Step-by-step explanation:
The expressions provided are:
(i)
Simplify the first expression with as few symbols as possible:
(ii)
Simplify the second expression with as few symbols as possible:
Thus, the simplified expressions are (<em>x</em> + <em>y·</em>z' + <em>t</em>) and <em>x·</em>(<em>x</em> + <em>y</em>' + <em>z</em>) respectively.
Answer: 9 Apples
Step-by-step explanation:
Given the following :
Total number of bags = 12
Mean of the distribution(m) = 8
Number of apples (x):
6 - - - - 7 - - - - 8 - - - - 9 - - - - 10
Frequency (f) :
1 - - - - 4 - - - - 2 - - - - 3 - - - - 1
Therefore :
Let number of apples in the 12th bag = y
Frequency of 12th bag : (12 - 11) = 1
Mean of distribution(m) :
Sum of ( f * x) / sum of f
Sum of (f * x) = (6*1)+(7*4)+(8*2)+(9*3)+(10*1)+(y*1)
Sum of (f * x) = (6+28+16+27+10+y) = 87 + y
Sum of f = 12
From :
m = Sum of ( f * x) / sum of f
8 = (87 + y) / 12
87 + y = 12 * 8
87 + y = 96
y = 96 - 87
y = 9
Number of apples in 12th bag is 9 apples
Answer:
oof my depressed play list like dam
Step-by-step explanation:
Answer:
Step-by-step explanation:
Interpreting as: 6000
Input:
6000
Number line:
Number line
Number name:
six thousand
Roman numerals:
\!\(\("V"\)\&_\)M
Binary form:
1011101110000_2
Prime factorization:
2^4×3×5^3
Residues modulo small integers:
m | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9
6000 mod m | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 6
Properties:
6000 is an even number.
6000 is a number that cannot be written as a sum of 3 squares.
6000 has the representation 6000 = 3^5 5^2 - 75.
6000 divides 49^10 - 1.
Character code 6000:
| Tagbanwa letter sa
Unicode: U+1770 (decimal: 6000)
Mathematica: \:1770
(Tagbanwa)
First off, you have to find a common denominator between 6 and 9 which is 18, so to rewrite your equation using the common denominators it would be 15/18+(-8/18)-(-36/18) when you combine these it equals (7/18)-(-36/18)=43/18