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zimovet [89]
2 years ago
7

The length of a swimming pool is 10 ft shorter than twice the width. the length is 35 ft. what is the width

Mathematics
1 answer:
Hatshy [7]2 years ago
8 0
Okay so we need to figure out the width of the swimming pool using the length, and we know the width is 10 ft shorter than twice the width. I believe the easiest way to do this would be to first do 35-10, and then divide it in half. That gives us 12.5. To check our work I'll do the problem 12.5+12.5+10=35.

The width of the swimming pool is 12.5 ft.
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steposvetlana [31]

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  • Washer method

\displaystyle\pi\int_0^1\left(\left(x^{1/15}\right)^2-x^2\right)\,\mathrm dx=\pi\int_0^1\left(x^{2/15}-x^2\right)\,\mathrm dx=\pi\left(\frac{15}{17}-\frac13\right)=\boxed{\frac{28\pi}{51}}

  • Shell method

We have y=x^{1/15}\implies x=y^{15}. The curves x=y and x=y^{15} intersect at y=0 and y=1, with y\ge y^{15} over 0\le y\le1.

\displaystyle2\pi\int_0^1y\left(y-y^{15}\right)\,\mathrm dy=2\pi\int_0^1\left(y^2-y^{16}\right)\,\mathrm dy=2\pi\left(\frac13-\frac1{17}\right)=\boxed{\frac{28\pi}{51}}

6 0
3 years ago
Will literally make BRAINLIEST and marry you if you do this for me
Tanya [424]

Answer:

0.44

Step-by-step explanation:

See the picture below.

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Perhaps you know SOHCAHTOA, where SOH means sine, opposite, hypotenuse.

For angle J, leg LK is the opposite leg.

The hypotenuse of the triangle is the side opposite the right angle, teh angle of 90°, which is angle L, so the hypotenuse is side KJ.

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\sin J = 0.43820...

Answer: 0.44

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7 0
2 years ago
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In the circle below, suppose m VUX = 152° and mZUVW = 77º. Find the following.
bezimeni [28]

Given:

In the circle, m(\overarc{VUX})=152^\circ and m(\angle MUV)=77^\circ.

To find:

The following measures:

(a) m\angle VUX

(b) m\angle UXW

Solution:

According to the central angle theorem, the central angle is always twice of the subtended angle intercepted on the same same arc.

m(VUX)=2\times m\angle VWX

152^\circ=2\times m\angle VWX

\dfrac{152^\circ}{2}=m\angle VWX

76^\circ=m\angle VWX

In a cyclic quadrilateral, the opposite angles are supplementary angles.

UVWX is a cyclic quadrilateral. So,

m\angle VUX+m\angle VWX=180^\circ          [Opposite angles of a cyclic quadrilateral]

m\angle VUX+76^\circ=180^\circ

m\angle VUX=180^\circ-76^\circ

m\angle VUX=104^\circ

Now,

m\angle UXW+m\angle UVW=180^\circ          [Opposite angles of a cyclic quadrilateral]

m\angle UXW+77^\circ =180^\circ

m\angle UXW=180^\circ-77^\circ

m\angle UXW=103^\circ

Therefore, m\angle VUX=104^\circ  and m\angle UXW=103^\circ .

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2 years ago
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Mila [183]
<h3>Answer:  8</h3>

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