Pairs, in this case, relates to a group of 2 or more. We have 6 friends. Let's call them A,B,C,D,E,F. This will allow us to make a [some sort of] combination tree:
1. ABC against DEF
2. ABD against CEF
3. ABE against CDF
4. ABF against CDE
5. ACD against BFE
6. ACE against BDF
7. ACF against BDE
8. ADE against BCF
9. ADF against BCE
10. AEF against BCD
I believe there are 12 combinations... I just can't think of the last 2 though.
She left at 12:15. 10:45 plus 1 hour= 11:45 + 15 min +12 +15= 12:15
You gave no options but the simplest way to solve this is to set it equal to all of the answers to see if it is correct.
<span>P= IRT solve for T
To solve for T, you must get T on it's own on one side of the equals sign, with all the other terms on the other side.
IRT means that I and R are multiplied by T.
To get rid of them we must do the opposite of multiply, which is divide.
But because this is an equation, anything we do on one side of the equals sign, must be repeated on the other side.
So if we divide the right side by IR, we must also divide the left side by IR</span>
