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pshichka [43]
4 years ago
13

The elements in the periodic table are arranged in order of

Chemistry
1 answer:
Alenkinab [10]4 years ago
5 0

Answer:

dsgadsagsdgsd

Explanation:

You might be interested in
Ari dissolves 1 gram of sugar in 10 grams of water. What will be the mass of the dissolved sugar and water ? Explain your answer
adell [148]

Answer:

the answer would be 11 grams of water/sugar water

Explanation: its that because 11 grams plus 1 gram = 11 grams

even though it may seem it may just go away that mass has to go somewhere it just doesn't vanish from the earth.

5 0
3 years ago
What is the charge of 5protons 6 neutrons and 5 electrons
Darya [45]

Answer:  

In this case the mass number would be 11.

Explanation:

The mass number of an element is the sum of the protons and neutrons. The number of neutrons for a given element is the only number that can change and still have the identity of the element stay the same, (because the atomic number is the number of protons).

4 0
3 years ago
Atoms that differ only in the number of neutrons are called:
Natali [406]
The answer is C. Isotopes.

Isotopes are defined as two substances that have the same number of protons and electrons, but a different number of neutrons, and therefore a different atomic mass. For example, carbon-12 and carbon-14 are isotopes of each other.

Hope this helps!
8 0
3 years ago
Read 2 more answers
If a sample of copper is 215g, how many moles of copper atoms are in the sample?
shusha [124]

Answer:

3.38 moles.

Explanation:

The following data were obtained from the question:

Mass of copper (Cu) = 215 g

Number of mole of copper (Cu) =...?

The number of mole of copper (Cu) in 215 g can be obtained as follow:

Mass of copper (Cu) = 215 g

Molar mass of copper (Cu) = 63.55 g/mol

Number of mole of copper (Cu) =...?

Mole = mass /Molar mass

Mole of Cu = 215/63.55

Mole of Cu = 3.38 moles

Therefore, 3.38 moles of copper (Cu) is present in the sample.

6 0
4 years ago
Evaporation of Cane Sugar Solutions. An evaporator is used to concentrate cane sugar solutions. A feed of 10 000 kg/d of a solut
Vera_Pavlovna [14]

Answer:

Weight of solution produced = 5135 kg

Amount of water removed = 4865 kg

Explanation:

For the balance of mass, the incoming mass of sugar must be equal to the outgoing mass. So, the incoming mass (mi) is 38% of 10000 kg

mi = 0.38x10000 = 3800 kg

The outgoing mass (mo) must be 3800 kg, and it is 74% of the total mass (mt)

mo = 0.74xmt

0.74xmt = 3800

mt = 3800/0.74

mt = 5135 kg

This is the mass of solution produced.

The amount of water removed (wr) is the amount of water incoming (wi) less the amount of water outgoing (wo). Both will be the total mass less the mass of sugar :

wi = 10000 - 3800 = 6200 kg

wo = 5135 - 3800 = 1335 kg

wr = wi - wo

wr = 6200 - 1335

wr = 4865 kg

8 0
4 years ago
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