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11111nata11111 [884]
3 years ago
10

Given J(1, 1), K(3, 1), L(3, -4), and M(1, -4) and that J'(-1, 5), K'(1, 5), L'(1, 0), and M'(-1, 0). What is the rule that tran

sforms preimage JKLM to
image J'K'L'M' ?
Mathematics
1 answer:
anastassius [24]3 years ago
5 0
(x; y) -> (x - 2; y + 4)

J(1; 1) ⇒ J'(1 - 2; 1 + 4) = (-1; 5)

K(3; 1) ⇒ K'(3 - 2; 1 + 4) = (1; 5)

L(3;-4) ⇒ L'(3 - 2; -4 + 4) = (1; 0)

M(1;-4) ⇒ M'(1 - 2;-4 + 4) = (-1; 0)


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kumpel [21]

Answer:

Step-by-step explanation:

Hello!

You have the growth of 12 plants over a week (cm)

To construct a box plot you have to identify the 1st, 2nd, and 3rd Quartiles for the box and the maximum and minimum values for the whiskers.

Box

1st Quartile (Q₁)

Is the value of the data set that separates the bottom 25% from the top 75%. First, you need to calculate its position:

PosQ₁= n/4= 12/4= 3

So the first quartile is the third value.

6, 7, 7, 8, 8, 8, 9, 9, 10, 11, 11, 14

Q₁= 7

2nd Quartile/ Median (Q₂/Me)

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The second quartile in the 6th value.

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3rd Quartile (Q₃)

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The third quartile is the 9th value.

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The left whisker extends from the Q₁ to the minimum value.

The right whisker extends from the Q₃ to the maximum value.

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Max= 14

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The box plot that best displays a summary of the data, is C.

I hope this helps!

3 0
3 years ago
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allochka39001 [22]

Answer:

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Step-by-step explanation:

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2 years ago
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mars1129 [50]
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S_A_V [24]

Answer:

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Step-by-step explanation:

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