A large emerald with a mass of 378.24 grams was recently discovered in a mine. If the density of the emerald is 2.76grams over c

Question

3 years ago

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A large emerald with a mass of 378.24 grams was recently discovered in a mine. If the density of the emerald is 2.76grams over c

entimeters cubed, what is the volume? Round to the nearest hundredth when necessary, and only enter numerical values, which can include a decimal point. Answer for Blank 1: __________________

Mathematics

1 answer:

bogdanovich [222] · Answer 1 · 2021-12-30T11:02:30+03:00

Answer:

Volume of emerald = 137.04cm³

Step-by-step explanation:

Given that:

Mass of emerald = 378.24grams

Density of emerald = 2.76grams/cm³

Volume = ?

The equation for this relationship is ρ = m / V in which ρ is density, m is mass (kg or g) and V is volume (cm³ or m³) making the density unit kg/m³ or g/cm³.

Therefore

Density = mass/volume

Volume = Mass/density

i.e

Volume of emerald = Mass of emerald / Density of emerald

Volume of emerald = 378.24grams / 2.76grams/cm³

Volume of emerald = 137.043cm³ ~137.04cm³

Volume of emerald =137.04cm³