Ur not dumb I’m the dumb one XD
Mark as brainiest
1) place the compass needle on the external point r.2) make the compass width greater than the distance from r to the given line.
3) draw an arc cutting the given line at two points.
4) mark and label the points of intersection p and q.
5) without changing the compass width, move the compass needle to q and draw another arc below the line crossing the previous arc.
6) move the compass needle to p and make an arc below the line.
7) mark and label the point of intersection s.
8) draw a line from the external point r to the point where the arcs intersect, s.
9) line rs is perpendicular to line pq and passes through the external point r.
<h3>
Answer: y = 5x+3</h3>
Explanation:
Parallel lines always have equal slopes, but different y intercepts.
Line K has a slope of 5, which means line L also has this slope too. Refer to the y = mx+b form.
Plug in the coordinates of (-2,-7) as well as the slope mentioned and solve for b.
y = mx+b
-7 = 5(-2) + b
-7 = -10+b
-7+10 = b
3 = b
b = 3
The y = mx+b updates to the final answer of y = 5x+3
I solved the iniquity for x, and your solution should be x < 2! Sorry if its not
