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Lorico [155]
3 years ago
12

Mercury from the Sun is approximately 5.8 ⋅ 107 kilometers, and the distance of Earth from the Sun is 1.5 ⋅ 108 kilometers. Abou

t how many more kilometers is the distance of Earth from the Sun than the distance of Mercury from the Sun?
Mathematics
1 answer:
Usimov [2.4K]3 years ago
7 0
1,I believe.  : )  Hope it helps!
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Given that EF is a diameter of circle D, which of the following arcs must be a major arc?
Rainbow [258]

Answer:

Arc ECG is the major arc

Step-by-step explanation:

Arc ECG is made by an angle which is greater than 180°.

All the other arcs listed are made by angles which are 180° or less than.

The greater the angle measure the greater the arc length.

8 0
3 years ago
The summer monsoon brings 80% of India's rainfall and is essential for the country's agriculture.
Natasha_Volkova [10]

Answer:

Step 1. Between 688 and 1016mm. Step 2. Less than 688mm.

Step-by-step explanation:

The <em>68-95-99.7 rule </em>roughly states that in a <em>normal distribution</em> 68%, 95% and 99.7% of the values lie within one, two and three standard deviation(s) around the mean. The z-scores <em>represent values from the mean</em> in a <em>standard normal distribution</em>, and they are transformed values from which we can obtain any probability for any normal distribution. This transformation is as follows:

\\ z = \frac{x - \mu}{\sigma} (1)

\\ \mu\;is\;the\;population\;mean

\\ \sigma\;is\;the\;population\;standard\;deviation

And <em>x</em> is any value which can be transformed to a z-value.

Then, z = 1 and z = -1 represent values for <em>one standard deviation</em> above and below the mean, respectively; values of z = 2 and z =-2, represent values for two standard deviations above and below the mean, respectively and so on.

Because of the 68-95-99.7 rule, we know that approximately 95% of the values for a normal distribution lie between z = -2 and z = 2, that is, two standard deviations below and above the mean as remarked before.

<h3>Step 1: Between what values do the monsoon rains fall in 95% of all years?</h3>

Having all this information above and using equation (1):

\\ z = \frac{x - \mu}{\sigma}  

For z = -2:

\\ -2 = \frac{x - 852}{82}

\\ -2*82 + 852 = x

\\ x_{below} = 688mm

For z = 2:

\\ 2 = \frac{x - 852}{82}

\\ 2*82 = x - 852

\\ 2*82 + 852 = x

\\ x_{above} = 1016mm

Thus, the values for the monsoon rains fall between 688mm and 1016mm for approximately 95% of all years.

<h3>Step 2: How small are the monsoon rains in the driest 2.5% of all years?</h3>

The <em>driest of all years</em> means those with small monsoon rains compare to those with high values for precipitations. The smallest values are below the mean and at the left part of the normal distribution.

As you can see, in the previous question we found that about 95% of the values are between 688mm and 1016mm. The rest of the values represent 5% of the total area of the normal distribution. But, since the normal distribution is <em>symmetrical</em>, one half of the 5% (2.5%) of the remaining values are below the mean, and the other half of the 5% (2.5%) of the remaining values are above the mean. Those represent the smallest 2.5% and the greatest 2.5% values for the normally distributed data corresponding to the monsoon rains.

As a consequence, the value <em>x </em>for the smallest 2.5% of the data is precisely the same at z = -2 (a distance of two standard deviations from the mean), since the symmetry of the normal distribution permits that from the remaining 5%, half of them lie below the mean and the other half above the mean (as we explained in the previous paragraph). We already know that this value is <em>x</em> = 688mm and the smallest monsoons rains of all year are <em>less than this value of x = </em><em>688mm</em>, representing the smallest 2.5% of values of the normally distributed data.

The graph below shows these values. The shaded area are 95% of the values, and below 688mm lie the 2.5% of the smallest values.

3 0
3 years ago
Find the value of the unknown number in the proportion 17/80=p/100
rjkz [21]
17/80 = p/100

p = 17/80 * 100

p = 0.2125 * 100

p = 21.25
8 0
4 years ago
I need help with this please!
Gennadij [26K]

Answer:

5ft

Step-by-step explanation:

perimeter=l+l+w+w

l=12

p=24+2w

34-24=10

10/2=5

8 0
2 years ago
The perimeter of the warehouse can be modeled by which of the following? P = 4(348 feet) P = (348 feet)2 P = 2(348 feet) + 2(348
Nikitich [7]
P= 4(348) because assuming the wear house has four sides that is the only logical answer
3 0
3 years ago
Read 2 more answers
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