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3 years ago

Using the Associative Property which expression is equivalent to (2+x)+4=

Mathematics

1 answer:

Anna35 [415]3 years ago

6 0

Answer:

x+6

Step-by-step explanation:

The given expression is (2+x)+4.

The associative property is :

(a+b)+c= a+(b+c)

Here,

a = 2, b = x and c = 4

So,

(2+x)+4 = 2+(x+4)

= x+6

So, the equivalent expression is x+6.

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Write an equation of a line in slope-intercept form that passes through the point (8, 9) and has a slope of 3.

Komok [63]

Answer:

y=3x-15

Step-by-step explanation:

y-y1=m(x-x1)

y-9=3(x-8)

y=3x-24+9

y=3x-15

6 0

2 years ago

The product od 2 and y is at least 10

alexgriva [62]

Hello There!

It could be represented by this:
$xy \geq 10$

Hope This Helps You!
Good Luck :)

- Hannah ❤

8 0

3 years ago

Expresion 2 5+4X2+6-2X2-1 Insert parentheses in Expression 2 so that it has a value of 19. Then show why your expression has a v

solong [7]

(5+4+6-2)×2×2-1
(9-4)×2×2-1
5×2×2--1
10×2-1
20-1
19

3 0

3 years ago

Math help please help... ive been stuck on this, thank you so much !!!!!

mr_godi [17]

Answer: (-3,4) and (9,20)

I think these two points will make the answer you have been looking for.

3 0

3 years ago

Suppose that two openings on an appellate court bench are to be filled from current municipal court judges. The municipal court

Ksju [112]

Answer:

$(a)\dfrac{92}{117}$

$(b)\dfrac{8}{39}$

$(c)\dfrac{25}{117}$

Step-by-step explanation:

Number of Men, n(M)=24

Number of Women, n(W)=3

Total Sample, n(S)=24+3=27

Since you cannot appoint the same person twice, the probabilities are <u>without replacement.</u>

(a)Probability that both appointees are men.

$P(MM)=\dfrac{24}{27}X \dfrac{23}{26}=\dfrac{552}{702}\\=\dfrac{92}{117}$

(b)Probability that one man and one woman are appointed.

To find the probability that one man and one woman are appointed, this could happen in two ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.

P(One man and one woman are appointed) $=P(MW)+P(WM)$

$=(\dfrac{24}{27}X \dfrac{3}{26})+(\dfrac{3}{27}X \dfrac{24}{26})\\=\dfrac{72}{702}+\dfrac{72}{702}\\=\dfrac{144}{702}\\=\dfrac{8}{39}$

(c)Probability that at least one woman is appointed.

The probability that at least one woman is appointed can occur in three ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.
Two women are appointed

P(at least one woman is appointed) $=P(MW)+P(WM)+P(WW)$

$P(WW)=\dfrac{3}{27}X \dfrac{2}{26}=\dfrac{6}{702}$

In Part B, $P(MW)+P(WM)=\frac{8}{39}$

Therefore:

$P(MW)+P(WM)+P(WW)=\dfrac{8}{39}+\dfrac{6}{702}\\$P(at least one woman is appointed)=\dfrac{25}{117}$

5 0

3 years ago