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Diano4ka-milaya [45]
3 years ago
5

Using the Associative Property which expression is equivalent to (2+x)+4=

Mathematics
1 answer:
Anna35 [415]3 years ago
6 0

Answer:

x+6

Step-by-step explanation:

The given expression is (2+x)+4.

The associative property is :

(a+b)+c= a+(b+c)

Here,

a = 2, b = x and c = 4

So,

(2+x)+4 = 2+(x+4)

= x+6

So, the equivalent expression is x+6.

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Write an equation of a line in slope-intercept form that passes through the point (8, 9) and has a slope of 3.
Komok [63]

Answer:

y=3x-15

Step-by-step explanation:

y-y1=m(x-x1)

y-9=3(x-8)

y=3x-24+9

y=3x-15

6 0
2 years ago
The product od 2 and y is at least 10
alexgriva [62]
Hello There!

It could be represented by this:
xy \geq 10

Hope This Helps You!
Good Luck :) 

- Hannah ❤
8 0
3 years ago
Expresion 2 5+4X2+6-2X2-1 Insert parentheses in Expression 2 so that it has a value of 19. Then show why your expression has a v
solong [7]
(5+4+6-2)×2×2-1
(9-4)×2×2-1
5×2×2--1
10×2-1
20-1
19
3 0
3 years ago
Math help please help... ive been stuck on this, thank you so much !!!!!
mr_godi [17]

Answer: (-3,4) and (9,20)

I think these two points will make the answer you have been looking for.

3 0
3 years ago
Suppose that two openings on an appellate court bench are to be filled from current municipal court judges. The municipal court
Ksju [112]

Answer:

(a)\dfrac{92}{117}

(b)\dfrac{8}{39}

(c)\dfrac{25}{117}

Step-by-step explanation:

Number of Men, n(M)=24

Number of Women, n(W)=3

Total Sample, n(S)=24+3=27

Since you cannot appoint the same person twice, the probabilities are <u>without replacement.</u>

(a)Probability that both appointees are men.

P(MM)=\dfrac{24}{27}X \dfrac{23}{26}=\dfrac{552}{702}\\=\dfrac{92}{117}

(b)Probability that one man and one woman are appointed.

To find the probability that one man and one woman are appointed, this could happen in two ways.

  • A man is appointed first and a woman is appointed next.
  • A woman is appointed first and a man is appointed next.

P(One man and one woman are appointed)=P(MW)+P(WM)

=(\dfrac{24}{27}X \dfrac{3}{26})+(\dfrac{3}{27}X \dfrac{24}{26})\\=\dfrac{72}{702}+\dfrac{72}{702}\\=\dfrac{144}{702}\\=\dfrac{8}{39}

(c)Probability that at least one woman is appointed.

The probability that at least one woman is appointed can occur in three ways.

  • A man is appointed first and a woman is appointed next.
  • A woman is appointed first and a man is appointed next.
  • Two women are appointed

P(at least one woman is appointed)=P(MW)+P(WM)+P(WW)

P(WW)=\dfrac{3}{27}X \dfrac{2}{26}=\dfrac{6}{702}

In Part B, P(MW)+P(WM)=\frac{8}{39}

Therefore:

P(MW)+P(WM)+P(WW)=\dfrac{8}{39}+\dfrac{6}{702}\\$P(at least one woman is appointed)=\dfrac{25}{117}

5 0
3 years ago
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