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lord [1]
3 years ago
12

A 43 degree angle can be classified as which angle type ?

Mathematics
2 answers:
jeyben [28]3 years ago
5 0

Answer: Acute Angle

Step-by-step explanation:

Any angle 89 degrees or less will identify as an acute angle.  

Sonbull [250]3 years ago
5 0

Hi there! My name is Zalgo and I am here to help you out today. A 43 degree angle is classified as an "acute angle". An Acute Angle is any angle under 90 degrees. A Right Angle is any angle at 90 degrees and an Obtuse Angle is any angle over 90 degrees. There is a 4th angle, but most teachers don't go over it and it isn't too important, so I see why, but it is called a Straight Angle. It is any angle that is 180 degrees.

I hope that this helps! :D

"Stay Brainly and stay prod!" - Zalgo

(By the way, can you mark me as Brainliest? I'd greatly appreciate it! Thank you! XP)

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Of the 950 students enrolled in a soccer league, 42% are in middle school. How many students in the soccer league are in middle
Ipatiy [6.2K]

Answer:

551

Step-by-step explanation:

I used a calculator.

3 0
3 years ago
Which expression is equivalent to 5(2x + 10)?
Ymorist [56]
E. 10x + 50
First you would multiply 5 times 2x that gets you 10x then you would do 5 times 10 to get 50!
7 0
3 years ago
Use the following vectors to answer parts​ (a) and​ (b). v1equals=[Start 3 By 1 Matrix 1st Row 1st Column 1 2nd Row 1st Column n
erik [133]

Answer:

(1) No matter what's the value of h, \vec{v}_3 is never in the span of \vec{v}_1 and \vec{v}_2.

(2) The three vectors \vec{v}_1, \vec{v}_2, and \vec{v}_3 are always linearly dependent for all real h.

Step-by-step explanation:

<h3>(a)</h3>

If \vec{v}_3 is in the span of \vec{v}_1 and \vec{v}_2, there need to exist real a and b such that

a\; \vec{v}_1 + b\; \vec{v}_2 = \vec{v}_3.

Assume that such a and b do exist.

In other words,

\displaystyle a \left[\begin{array}{c}{1 \\ -4\\2} \end{array}\right] + b\left[\begin{array}{c}{-4 \\ 16\\-8}\end{array}\right] = \left[\begin{array}{c}5 \\7 \\ h\end{array}\right].

\displaystyle \left[\begin{array}{c}{a \\ -4a\\2a} \end{array}\right] + \left[\begin{array}{c}{-4b \\ 16b\\-8b}\end{array}\right] = \left[\begin{array}{c}5 \\7 \\ h\end{array}\right].

\left\{\begin{array}{rrcr} a & - 4b &=& 5\\ -4a & + 16b &= &7\\2a & -8b & =&h\end{aligned}\right..

Rewrite as an augmented matrix and row-reduce:

\displaystyle \left[ \begin{array}{cc|c} 1 & -4 & 5 \\ -4 & 16 & 7 \\ 2 & -8 & h\end{array}\right].

(Add four times row one to row two and -2 times row one to row three.)

\displaystyle \sim \left[ \begin{array}{cc|c} 1 & -4 & 5 \\ 0 & 0 & 27 \\ 0 & 0 & h - 10\end{array}\right].

Note that in row two,

  • Left-hand side: 0;
  • Right-hand side: 27\neq 0.

In other words, this system is inconsistent. There's no real a and b that would satisfy the condition

a\; \vec{v}_1 + b\; \vec{v}_2 = \vec{v}_3.

Hence \forall h \in \mathbb{R}, \quad \vec{v}_3\not \in \text{Span}\{\vec{v}_1, \vec{v}_2\}.

There's no real h that allows h, \vec{v}_3 to be part of the span of \vec{v}_1 and \vec{v}_2.

<h3>(b)</h3>

If the three vectors are linearly dependent, at least one of them can be expressed as the linear combination of the other two.

Note that

\vec{v}_2 = (-4)\vec{v}_1 + 0 \; \vec{v}_3. In other words, \vec{v}_2 can be written as the linear combination of the other two vectors. Additionally, since the coefficient in front of \vec{v}_3 is zero, neither the exact value of \vec{v}_3 nor the value of h will make a difference. Therefore, for all h \in \mathbb{R}, the three vectors \vec{v}_1, \vec{v}_2, and \vec{v}_3 are linearly dependent.

8 0
3 years ago
William has a 26 -liter glass tank. First, he wants to put some marbles in it, all of the same volume. Then, he wants to fill th
madreJ [45]

Subtract the volume of the water from the volume of the tank to get the total volume of the marbles.

26 liters - 20.9 liters = 5.1 liters

He has 20.9 liters of water.

He has 85 marbles that add up to 5.1 liters of volume.

To find the volume of one marble, we divide 5.1 liters by 85.

(5.1 liters)/85 = 0.06 liters

The volume of each marble is 0.06 liters.

If he uses 200 marbles, the the marbles will occupy 200 * 0.06 liters = 12 liters.

The volume of the tank is 26 liters. 12 liters of volume is occupied by the marbles. The rest of the volume is water.

26 liters - 12 liters = 14 liters

4 0
3 years ago
Please help it’s urgent
yawa3891 [41]

Answer:

1) 12/18

2) 15/25

3) 32/40

4) 6/14

5)  8/15

6) 16/24

7. 12/27

Step-by-step explanation:

7 0
3 years ago
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