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never [62]
3 years ago
8

Graph quadrilateral ABCD and find the most precise name (square, rectangle,

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
8 0

Answer:

Kite

Step-by-step explanation:

To graph quadrilateral with points:

A(-1,-2)

B(5,1)

C(-3,1)

D(-1,4)

Thus, we graph the the given points and join the corners. The quadrilateral formed has the following features:

Measure of segment AB= Measure of segment BD = 6.708 units

Measure of segment AC= Measure of segment CD = 3.605 units

Thus, adjacent pair of sides of the quadrilateral are congruent.

Major diagonal BC cuts the minor diagonal AD at point E such that:

Measure of segment AE= Measure of segment ED = 3 units

m∠AEB = m∠DEB = 90°

Thus, major diagonal is a perpendicular bisector of the minor diagonal.

The above stated features fulfills the criterion of a kite.

Hence, the given quadrilateral ABCD is a kite.

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A is 7 4 and 3..B is the same...This is my first time with this kind of problem....
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3 years ago
The Roman Numeral MCM means​
GuDViN [60]

Answer:

See explanation below

Step-by-step explanation:

The Roman Numeral MCM means 1900.

The first M is 1000, CM means 900 ==> 1000 + 900 = 1900

8 0
3 years ago
Solve the system of equations.
vova2212 [387]

Answer:

8x = 32

x = 4

y = 6

Step-by-step explanation:

2.5y + 3x = 27

5x – 2.5y = 5

_____________

8x = 32 (equation obtained after adding the two equations)

x = 32/8

x = 4

Plug x = 4 in 2.5y + 3x = 27

2.5y + 3*4 = 27

2.5y + 12 = 27

2.5y = 27 - 12

2.y5= 15

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8 0
3 years ago
An employee worked 160.5 hours in may, 165.75 hours in June and 152.25 hours in july.
Vaselesa [24]
To find the average, you have to add everything up and divide by the amount that you have. In this case, you need to add together 160.5, 165.75 and 152.25, and then divide by 3.
160.5+165.75+152.25= 478.5
You've then got to divide this by three.
478.5/3= 159.5
Therefore, the average hour worked each month bu the employee is 159.5
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5 0
4 years ago
The NCAA is interested in estimating the difference in mean number of daily training hours for men and women athletes on college
hammer [34]

Answer:

s^2_p = \frac{9*0.3^2 +9*0.4^2}{10+10-2}=0.125

s_p =\sqrt{0.125}=0.354

(2.7 -2.4) - 2.1*0.354\sqrt{\frac{1}{10}+\frac{1}{10}}=-0.032  

(2.7 -2.4)+ 2.1*0.354\sqrt{\frac{1}{10}+\frac{1}{10}}=0.632  

Step-by-step explanation:

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Data given

\bar X_M = 2.7 represent the sample mean for men

\bar X_F = 2.4 represent the sample mean for women

s_M = 0.3 represent the sample deviation for men

s_F = 0.4 represent the sample deviation for women

n_M = 10 sample size of male

n_F =10 sample size of women

The confidence interval is given by:

(\bar X_M -\bar X_F) \pm t_{\alpha/2} S_p \sqrt{\frac{1}{n_M}+\frac{1}{n_F}}   (1)

The polled variance can be calculated with this formula:

s^2_p = \frac{9*0.3^2 +9*0.4^2}{10+10-2}=0.125

s_p =\sqrt{0.125}=0.354

For a confidence of 95% the value for the significance is \alpha=1-0.95=0.05 and \alpha/2 = 0.025, the degrees of freedom are given by:

df = n_M + n_F -2= 10+10-2=18

And the critical value can be calculated with the following formula in excel: "=T.INV(1-0.025,18)" and we got t_{\alpha/2}=2.1

Now we can replace into the confidence interval:

(2.7 -2.4) - 2.1*0.354\sqrt{\frac{1}{10}+\frac{1}{10}}=-0.032  

(2.7 -2.4)+ 2.1*0.354\sqrt{\frac{1}{10}+\frac{1}{10}}=0.632  

6 0
3 years ago
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