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NARA [144]
3 years ago
12

You are measuring the dimensions of the floor in your bedroom because you are planning to buy new carpet. Which unit of measure

is the most appropriate to use in this situation?
A) square feet B) square miles C) square inches D) square centimeters
Mathematics
1 answer:
aivan3 [116]3 years ago
3 0
A) square feet
if you are measuring the room u do not use centimeters because it to small to measure and take forever to measure the room
mile are long so that won't work
inches take a long time to measure a room that would not work
so a is the answer
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Find the degree of each polynomial and indicate whether the polynomial is a monomial, binomial or trinomial, or none of these. -
SIZIF [17.4K]

Answer:

Monomial, degree is 5

Step-by-step explanation:

7 0
2 years ago
Please help me!!!!!!
Nikitich [7]

Answer: 243, 729

<u>Step-by-step explanation:</u>

1, 3, 9, 27, 81    is a geometric sequence where r = 3

a₁ = 1

a₂ = 1 x 3 = 3

a₃ = 3 x 3 = 9

a₄ = 9 x 3 = 27

a₅ = 27 x 3 = 81

To find the next two terms, multiply the previous term by 3:

a₆ = 81 x 3 = 243

a₇ = 243 x 3 = 729

8 0
3 years ago
Pentagon RSTUV is circumscribed about a circle. What is the value of x if RS = 8, ST = 12, TU = 15, UV = 9, and VR = 12?
ivanzaharov [21]

Answer:

The value of x is 7 ⇒ 1st answer

Step-by-step explanation:

* Lets revise a fact in the circle

- The two tangents drawn from a point out side the circle are equal

∵ RSTUV is circumscribed about a circle

∴ Each side of the pentagon is a tangent to the circle

- Look to the attached figure to know how we will solve the problem

- Each tangent divided into two parts

# RS = x + y

∵ RS = 8

∴ x + y = 8 ⇒ (1)

# RV = x + n

∵ RV = 12

∴ x + n = 12 ⇒ (2)

- Subtract (2) from (1)

∴ y - n = -4 ⇒ (3)

# ST = y + z

∵ ST = 12

∴ y + z = 12 ⇒ (4)

# TU = z + m

∵ TU = 15

∴ z + m = 15 ⇒ (5)

- Subtract (5) from (4)

∴ y - m = -3 ⇒ (6)

# UV = m + n

∵ UV = 9

∴ m + n = 9 ⇒ (7)

- Add (6) and (7)

∴ y + n = 6 ⇒ (8)

- Lets solve equation (3) and equation (8) to find y

∵ y - n = -4 ⇒ (3)

∵ y + n = 6 ⇒ (8)

- Add (3) and (8)

∴ 2y = 2 ⇒ divide two sises by 2

∴ y = 1

- Lets substitute the value of y in equation (1)

∵ x + y = 8 ⇒ (1)

∵ y = 1

∴ x + 1 = 8 ⇒ subtract (1) from both sides

∴ x = 7

* The value of x is 7

3 0
3 years ago
Do teachers find their work rewarding and satisfying? An article reports the results of a survey of 397 elementary school teache
Tju [1.3M]

Answer:

The 95% confidence interval would be given (0.0109;0.1651).  

We are confident at 95% that the difference between the two proportions is between 0.0109 \leq p_{elementary} -p_{High school} \leq 0.1651

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

p_A represent the real population proportion for elementary school  

\hat p_A =\frac{226}{397}=0.569 represent the estimated proportion for elementary school

n_A=397 is the sample size required for Brand A

p_B represent the real population proportion for high school teachers  

\hat p_B =\frac{129}{268}=0.481 represent the estimated proportion for high school teachers

n_B=268 is the sample size required for Brand B

z represent the critical value for the margin of error  

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})  

The confidence interval for the difference of two proportions would be given by this formula  

(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}  

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=1.96  

And replacing into the confidence interval formula we got:  

(0.569-0.481) - 1.96 \sqrt{\frac{0.569(1-0.569)}{397} +\frac{0.481(1-0.481)}{268}}=0.0109  

(0.569-0.481) + 1.96 \sqrt{\frac{0.569(1-0.569)}{397} +\frac{0.481(1-0.481)}{268}}=0.1651  

And the 95% confidence interval would be given (0.0109;0.1651).  

We are confident at 95% that the difference between the two proportions is between 0.0109 \leq p_{elementary} -p_{High school} \leq 0.1651

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