86.34 minutes was used to cool the soup to 80 °F
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How can we calculate this using Newton's Law of Cooling?</h3>
Newton's Law of Cooling can be computed as :
The initial temperature is been represent by T0 which is ( 100 F)
The temperature of surrounding is been given as (69 F)
The final temperature is been given as T
t = time
we were told that the temperature of the soup move to 95 F, using 15 minutes.
Hence, T = 95 F
t = 15 min
Then we can input the values into the above equation as :
if we simplify this , we have
Then 
Then we can find the value of k as :
k= -0.012
Then we have the new equation as
Then at T=80F
we have,
t=86.34
Then if we simplify , we have t=86.34 which implies that 86.34 minutes was used to cool the soup to 80 °F
Learn more about Newton's Law of Cooling at:
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We have been given a system of equations 
and 
. We are asked to find the solution of our given system of equations.
To solve our system of equations, we will equate both equations as:
Upon substituting in equation , we will get:
Therefore, the solution of our given system of equations would be 
and option A is the correct choice.
Answer:
Step-by-step explanation:
First, we write the rental cost with each company:
Company A 
Company B 
Where m: miles travelled
Now, we need to find "number of miles in a day at which the rental costs for Company A and Company B are the same". This means Pa = Pb. Then:
Solving the equation for m by taking 0.2m and 60 on both sides:
Finally, dividing 0.5 on both sides:
B. Identity property of division. Everything divided by 1 is itself.
You have to add all the numbers and then with that sum divide it by the number of numbers. In this case it would be 42+45+58+63+42+47+52=349. Now divide that by the numbers of numbers which in this case is 7, ~49.85(answer).
