Let V, be the rate in still water and let C = rate river current
If the boat is going :
upstream, its rate is V-C and if going
downstream, its rate is V+C,
But V = 5C, then
Upstream Rate: 5C - C = 4 C
Downstream rate: 5C+C = 6C
Time = distance/Rate, (or time = distance/speed) , then:
Upstream time 12/4C and
Downstream time: 12/.6C
Upstream time +downstream time:= 2h30 ' then:
12/4C + 12/.6C = 2.5 hours
3/C + 2/C = 5/2 (2.5 h = 5/2)
Reduce to same denominator :
5C = 10 and Rate of the current = 2 mi/h
Answer:
(5√5)(6√4) = 5 * √5 * 6 * 2 = 60*√5
Answer:
A and D
Step-by-step explanation:
A rounds to 0.2
D rounds to 5.26
Answer:
Step-by-step explanation:
Subtract 7y7y from both sides.
-4x=18-7y−4x=18−7y
2 Divide both sides by -4−4.
x=-\frac{18-7y}{4}x=−
4
18−7y
When a=6,
2a - 3 = 2(6) - 3 = 12 - 3 = <em><u>9</u></em>
