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Aleks [24]
2 years ago
12

Solving with percent and percent problems

Mathematics
1 answer:
Marysya12 [62]2 years ago
8 0
Well, if 0.4% was defected, then 99.6% of the parts are good, because 100-0.4 is 99.6. Multiply 99.6% with 54650, and you get 54431.4. You should round down, because you can't have parts of parts. So, 54431 parts were good.  
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8 out of 10 words were correct what percentage of the word spelled correctly
exis [7]
8/10*100=80%

-80% of the words were spelled correctly.

remember, whenever u get a challenge like this, always to multiply the given fraction by 100 (as stated above)

-hope it gives u an brief idea how to solve questions like these:)


3 0
2 years ago
3x + 4y = 27 5x - 3y = 16
Arturiano [62]

Answer:

x = 5 , y = 3

Step-by-step explanation:

Solve the following system:

{3 x + 4 y = 27 | (equation 1)

5 x - 3 y = 16 | (equation 2)

Swap equation 1 with equation 2:

{5 x - 3 y = 16 | (equation 1)

3 x + 4 y = 27 | (equation 2)

Subtract 3/5 × (equation 1) from equation 2:

{5 x - 3 y = 16 | (equation 1)

0 x+(29 y)/5 = 87/5 | (equation 2)

Multiply equation 2 by 5/29:

{5 x - 3 y = 16 | (equation 1)

0 x+y = 3 | (equation 2)

Add 3 × (equation 2) to equation 1:

{5 x+0 y = 25 | (equation 1)

0 x+y = 3 | (equation 2)

Divide equation 1 by 5:

{x+0 y = 5 | (equation 1)

0 x+y = 3 | (equation 2)

Collect results:

Answer:  {x = 5 , y = 3

4 0
3 years ago
Points to whoever wants them ig<br> ima delete the account anyways
Marina CMI [18]

Answer:

thankyou for points!!!!!!!!!!!

5 0
2 years ago
Read 2 more answers
Explain why it is helpful to know the basic function shapes and discuss some ways to remember them.
postnew [5]
<h3>Explain why it is helpful to know the basic function shapes and discuss some ways to remember them. </h3>
  • Knowing the basic function shapes and discuss some ways to remember them is helpful because this is useful tools in the creation of mathematical models because we constantly make theories about the relationships between variables in nature and society. Functions in school mathematics are typically defined by an algebraic expression and have numerical inputs and outputs.
3 0
2 years ago
6d+23=14(d−2) what is the answer
Amanda [17]
6d+23=14(d-2)
6d+23=14d-28
6d+51=14d
51=8d
51/8= 6.375 or 6 3/8

Hope this helps :)
4 0
2 years ago
Read 2 more answers
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