Website 1
y=1.50x+30
Website 2
y=2x+30
Hope this helps!
Here you would use right triangle trig (SOH CAH TOA)
So first draw a right triangle. Imagine youre standing at the angle opposite the right angle which is the one on the ground.This angle is the 41°. Now Imagine the balloon is as the angle above the right triangle. Well since the balloon is 1503 m from his location this would be the hypotenuse. SInce we are trying to find the height (x) we would use sine since
sine = opposite/hypotenuse . Now lets solve make sure calculator is in degree mode:
sin41 = x/1503 multiply both sides by 1503 to cancel it out
1503sin41 = x plug into calculator
x = 986.057 ft
The balloon is 986.057 feet above the ground.
<span>7x - 5y =21
-7 -7
5y = 14
---- -----
5 5
y= 2.8
(4,2.8)</span>
The second equation is <span>-5-2y=2, then
</span>
<span>-2y=2-(-5),
</span>
-2y=2+5,
-2y=7,
y=7÷(-2),
y=-3.5.
The first equation is 2x+5y=16, subtitude y=-3.5 in this equation, then
2x+5·(-3.5)=16,
2x-17.5=16,
2x=16-(-17.5),
2x=16+17.5,
2x=33.5,
x=33.5÷2,
x=16.75.
Answer: (16.75,-3.5)
