It’s the first one!! :)))
X+y=31.5
x-y=5.25
add 2 equations
x+y+x-y=31.5+5.25
2x=36.75
x=18.375
y=31.5-18.375=13.125
check : 18.375+13.125=31.5, 18.375-13.125=5.25
so
Answer:
18.375 and 13.125
7x/x-4 * x/x+7
mutiply the numerators together
(7x)(x)= 7x^ 2
mutiply the denominators together
(x-4)(x+7)
(x)(x)(7)(x)= x^2+7x
(-4)(x)(-4)(7)= -4x-28
x^2+7x-4x-28
x^2+3x-28
Answer:
7x^2/x^ 2+3x-28
Answer:
yes
Step-by-step explanation:
The line intersects each parabola in one point, so is tangent to both.
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For the first parabola, the point of intersection is ...
y^2 = 4(-y-1)
y^2 +4y +4 = 0
(y+2)^2 = 0
y = -2 . . . . . . . . one solution only
x = -(-2)-1 = 1
The point of intersection is (1, -2).
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For the second parabola, the equation is the same, but with x and y interchanged:
x^2 = 4(-x-1)
(x +2)^2 = 0
x = -2, y = 1 . . . . . one point of intersection only
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If the line is not parallel to the axis of symmetry, it is tangent if there is only one point of intersection. Here the line x+y+1=0 is tangent to both y^2=4x and x^2=4y.
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Another way to consider this is to look at the two parabolas as mirror images of each other across the line y=x. The given line is perpendicular to that line of reflection, so if it is tangent to one parabola, it is tangent to both.
Answer:
The quotient is the solution to a division sum.
Step-by-step explanation:
A single number can not have a quotient.