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4 years ago

Charlie runs at a speed of 3 yards per second. about how many miles per hour does charlie run?

2 answers:

5 0

3 * 60 = 180 yards per minute
180 * 60 = 10800 yards per hour
10800/1760 ≈ 6.14 miles per hour

harina [27]4 years ago

4 0

Points for the points

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Is the mean weight of female college students still 59.4 kg? To test this, you take a random sample of 20 students, finding a me

adell [148]

Answer:

Correct option: (B)

Step-by-step explanation:

A one-sample t-test can be performed to determine whether the mean weight of female college students is still 59.4 kg.

The hypothesis can be defined as:

H₀: The mean weight of female college students has changed.

Hₐ: The mean weight of female college students has not changed.

The information provided is:

$\bar x=61.65\\s=6.39\\n=20\\\alpha =0.10$

As the there is no information about the population standard deviation we will use a t-test for the mean.

The test statistic is:

$t=\frac{\bar x-\mu}{\s/\sqrt{n}}=\frac{61.65-59.4}{6.39/\sqrt{20}}=1.57$

Decision rule:

If the if the p-value of the test is less than the significance level of the test α then the null hypothesis will be rejected and vice versa.

The degrees of freedom of the test is:

$df=n-1=20-1=19$

The test is two-tailed.

Compute the p-value of the test as follows:

$p-value=2\times P(t_{0.10/2, 19}$

*Use a t-table for the probability.

The p-value = 0.13 > α = 0.10

The null hypothesis was failed to be rejected.

As the null hypothesis was rejected it can be concluded that there is not sufficient evidence that the mean weight of female students has changed.

6 0

4 years ago

Hey I just wanted to know if anyone could help me out with this, I really would love the help.

abruzzese [7]

Answer:

3x-6 A.

Step-by-step explanation:

I would glady help anyone.

You welcome.

7 0

3 years ago

Given:

rusak2 [61]

Answer:the answer is c

Step-by-step explanation:

6 0

3 years ago

Which transformations are needed to change the parent cosine function to the cosine function below?

Otrada [13]

Question:

1. vertical stretch of 2, horizontal stretch to a period of 2 pi, phase shift of StartFraction pi Over 2 EndFraction units to the right, vertical shift of 1 unit up

2. vertical compression of 2, horizontal stretch to a period of StartFraction pi Over 4 EndFraction, phase shift of StartFraction pi Over 4 EndFraction units to the left, vertical shift of 2 units down

3. vertical compression of 2, horizontal compression to a period of 4 pi, phase shift of StartFraction pi Over 3 EndFraction units to the left, vertical shift of 1 unit down

4. vertical stretch of 2, horizontal compression to a period of StartFraction pi Over 2 EndFraction, phase shift of Pi units to the right, vertical shift of 1 unit down

Answer:

The correct option is;

4. Vertical stretch of 2, horizontal compression to a period of π/2, phase shift of π units to the right, vertical shift of 1 unit down

Step-by-step explanation:

Here, we have the parent cosine function given by y = cos(x)

A plot of the above function is attached

By comparison, it is observed that the transformation required to change the parent function includes;

1. Vertical stretch from the parent function of amplitude 1 to amplitude 2

2. A horizontal compression so that the period of one complete revolution is π/2 rather than 2·π in the parent cosine function

3. Phase shift of pi units to the right such that cos(π) = 1 rather than cos(2π) = 1 as it applies to the parent function

4. Shift of the y values from the symmetrical x-axis origin downwards by 1 unit such that the maximum y value of the doubly stretched transformation is 1 rather than 2