Dr. Hoover allot his time on Tuesday for an annual checkup is 147 minutes and for a sick visit is 42 minutes (Total 189 minutes)
On Wednesday appointment, he allot his time for an annual checkup is 147 minutes and for a sick visit is 21 minutes (Total 168 minutes)
solution
Let us assume, minutes for annual checkup denoted as x and
minutes for sick visit denoted as y
The equation of Tuesday visit is 
The equation of Wednesday visit is 
by changing the signs of the equation 2 and subtract it from the equation 1 we will get 1y = 21 minutes
to substitute y =1 in the equation 2 we get





then now we have substitute both x = 49 and y= 21 in equation ----- 2
we will prove that

so the Tuesday appointment , the time allotted for an annual checkup is 147 minutes and for a sick visit is 42 minutes (Total 189 minutes)
On Wednesday appointment, the time allotted for an annual checkup is 147 minutes and for a sick visit is 21 minutes (Total 168 minutes)
Answer:
T must be 3/(3+1) or 3/4ths of the way between point d and f.
Take (dx, dy) and add 3/4 (fx-dx, fy-dy) by components and that will be point T (Tx, Ty)
You find the distances between d and f in x and y and then move 3/4 of that distance from d.
Step-by-step explanation:
Im not too sure, I got the answer from my last test. It might be wrong
Answer:
In point slope form, this is y = (-5/2)x + 2. In standard form, it's (5/2)x + y = 2.
Step-by-step explanation:
y-6=-5/2 (x+4) has already been written in point-slope form. The slope of the line is -5/2 and the point on the line is (-4,6).
In slope-intercept form: add 6 to both sides of the original equation, obtaining y = 6 - (5/2)(x + 4), or y = 2 - (5/2)x, or y = (-5/2)x + 2
Answer:
that is the solution to the question