Answer:
Step-by-step explanation:
Formula
Sn = (a + a + (n - 1)*d) * n / 2
Givens
Sn = 60
a = 3
Solution
You want integer values for d and n
60 = (2*a + (n - 1)*d) * n/2 Multiply both sides by 2
120 = (2*3 + (n - 1)*d ) * n
120 = (6 + n*d - d) * n
120 = 6n + n^2*d - d*n
This gives some really wild results. I will list all of them here. and then discuss them.
These are the ones that give results without any question and are correct.
n d tn
2 54 3 57
3 17 3 20 37
4 8 3 11 19 27
Here are some that are the gift of the equation
20 0 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3
Now the equation says the following 3 are correct, but are they? Can you have a negative n? The equation says yes, but I doubt your instructor will.
-5 5
-1 63
-2 22
You can bring these up if you are in a classroom. I wouldn't if you have to submit this to a computer which has absolutely no ability whatever to think about exceptions. Even the 20 0 is one I wouldn't use.
Answer:
A).
650 + 35w> 825 + 15w
Step-by-step explanation:
Molly already has $650 set aside and adds $35 each week.
Lynn already has $825 set aside but adds only $15 each week
Let the number of weeks Molly's savings exceeds Lynn's savings be x. for Molly's savings= $650 + $35x
For Lynn savings = $825 + $15x
Fot Molly's savings to be greater than Lynn savings,then
$650 + $35x> $825 + $15x
G(x) = x²
a) To find g(1) substitute with x = 1 at the function g(x)
∴ g(1) = 1² = 1
b) substitute with x = -2 at the function g(x)
∴ g(-2) = (-2)² = 4
c) substitute with x = -x at the function g(x)
∴ g(-x) = (-x)² = x²
d) substitute with x = 2y at the function g(x)
∴ g(2y) = (2y)² = 4y²
e) substitute with x = 2+h at the function g(x)
∴ g(2+h) = (2+h)² = h² + 4h + 4
The three dimensional diagonal of a rectangular prism is:
d^2=x^2+y^2+z^2, and since this is a cube, x=y=z=s, and we are told that s=3
d^2=3s^2 and s=3
d^2=3(3^2)
d^2=3(9)
d^2=27
d=√27
