Answer:
no
Step-by-step explanation:
Answer:
When the price of a ticket = $0 or $40, there will be no revenue.
The revenue will be $500 if each ticket cost $37.3 or $2.68
Step-by-step explanation:
Let R(p) = p(200-5p)
when R(p) = 0
p(200-5p) = 0
p = 0 or 200-5p = 0
When the price of a ticket = $0 or $40, there will be no revenue.
when R(p) = 500
200p - 5p² = 500
5p² - 200p + 500 = 0
p = $37.3 or $2.68 (3 sig. fig.)
The required prices are $37.3 and $2.68
Part A: (no overtime) E = 18x. Please note that x cannot exceed 35, thus E cannot exceed $630.
Part B: T = 25y + 18x where x = 35 hours. Thus, T = 25y + 630.
Part C: T = $730. 730 = 630 + 25y. Subtract 630 from both sides. 100 = 25y. Divide both sides by 25. y = 4. This is the number of overtime hours -- remember that Dominic has already worked 35 hours non-overtime. 35 + 4 = $730.
Answer:
Step-by-step explanation:
3 (4 -6) = -8 is correct. The next step is to combine 4 and -6, obtaining
3(-2)
and this 3(-2) should equal -6, which is not the same as -8.
3(4 - 6) = 12 - 18, which differs from the student's solution. This is the reason for the wrong answer.
C. CENTER (-3, 5 ) : R =25
