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max2010maxim [7]
3 years ago
7

The speed of light is about 300,000 kilometers per second. Convert the speed to miles per hour. Round your answer to the nearest

hundred thousand miles per hour
Mathematics
2 answers:
Snezhnost [94]3 years ago
7 0
300000 km/sec x 3600 sec/hr=1080000000 km/hr
1080000000 km/hr / 1.6 km/m=675000000 mph
☺☺☺☺
Alex3 years ago
5 0

Answer:

671080887.619  miles/hour        

Step-by-step explanation:

Given : Speed of light = 300,000 kilometers per second

To Find:  Convert the speed to miles per hour

Solution :

1 kilometer = 0.621371 miles

3600 second = 1 hour

So, 1 second = \frac{1}{3600}

So, speed of light in miles per hour:

= \frac{300000\times 0.62137119224}{\frac{1}{3600}}

= \frac{300000\times 0.62137119224\times3600 }

= 671080887.619

Thus the speed of light is 671080887.619  miles/hour                                                      

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What is the reflection of image p(0,0) after two reflections first across x=-3 and
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<span>P (0, 0) across x = -3 will change the x value. From 0 to -3 which is 3 units down, so the reflection will be another 3 units down ( points are the same distance from the reflection line) so the new x-value is -6 now just do the same thing for the y-value and you will get an image of P¹ ( -6, -6 ) </span>
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3 years ago
) An engineer deploys a set of sensors. Each sensor reports its location as a point in two-dimensional space. The points are (2,
r-ruslan [8.4K]

Answer:

<em>The polygon area is </em>51.5 U^{2}<em />

Step-by-step explanation:

Points:

(2,7), (8,2), (6,11), (6,5), (11,6)

1. The area of the polygon could be calculate with the eqation:

A=\frac{1}{2}\left[\begin{array}{ccc}x_{1} &y_{1}\\x_{2} &y_{2}\\x_{3} &y_{3}\\x_{4} &y_{4}\\x_{5} &y_{5}\end{array}\right]

2. Replace the coordinates in equation for A:

A=\frac{1}{2}\left[\begin{array}{ccc}2&7}\\8&2\\6&11\\6&5\\11&6\end{array}\right]

3. Solve the determinant, and calculate A:

A=\frac{1}{2}\left[\begin{array}{ccc}2&7}\\8&2\\6&11\\6&5\\11&6\end{array}\right]\\A=\frac{1}{2}[(6)(7)+(11)(11)+(8)(6)+(6)(2)]-[(2)(11)+(6)(6)+(11)(2)+(8)(5)]\\A=\frac{1}{2}[42+121+48+12]-[22+36+22+40]\\A=\frac{1}{2}[223]-[120]\\\\A=\frac{1}{2}[103]=51,5 U^{2}

<em>The polygon area is </em>51.5 U^{2}<em />

8 0
4 years ago
What is the image of (0,6)(0,6) after a reflection over the y-axis?
kramer

The image of (0,6) after a reflection over the y-axis is (0, 6)

<h3>How to determine the image of (0,6) after a reflection over the y-axis?</h3>

The point is given as:

(0, 6)

The rule of reflection is given as:

Reflection over the y-axis

The rule of reflection over the y-axis is represented as:

(x, y) = (-x, y)

So, we have:

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Evaluate the expression

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Hence, the image of (0,6) after a reflection over the y-axis is (0, 6)

Read more about reflection at:

brainly.com/question/4289712

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8 0
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Answer:

20        

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In area you have to multiply so 10 x ? = 200

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