Given:
The graph of f(x).
To find:
The interval where f(x)>0.
Solution:
From the given graph it is clear that the graph of f(x) lies above the axis for the intervals (-4,-1) and (1,∞), so f(x)>0 for
and
.
The graph of f(x) lies below the axis for the intervals (-∞,-4) and (-1,1), so f(x)<0 for
and
.
Form the given options, interval
is the only interval for which the function lies above the x-axis.
Therefore, the correct option is A.
The length of an arc is given by (θ/360)2πr, where θ is the angle subtended by the arc at the center and r is the radius.
The angle θ in this case is 270°, while the radius is 7 feet, diameter is 14 feet
Thus the length of the of the cable will be;
=(270/360)× 22/7×14
= 0.75 × 44
= 33 feet
Answer: im rlly srry i need points but i will try my best
Step-by-step explanation:
the 3rd bar on componey 3 is longer than any other 1
4 1/4 +2 2/4 =6 3/4=total time
54/6.75=$8 per hour
![\huge\boxed{y=-2x+3}](https://tex.z-dn.net/?f=%5Chuge%5Cboxed%7By%3D-2x%2B3%7D)
Start off by finding the slope of the line with the formula
.
Substitute the values. ![\frac{1-3}{1-0}](https://tex.z-dn.net/?f=%5Cfrac%7B1-3%7D%7B1-0%7D)
Subtract. ![\frac{-2}{1}](https://tex.z-dn.net/?f=%5Cfrac%7B-2%7D%7B1%7D)
Simplify. ![-2](https://tex.z-dn.net/?f=-2)
is the slope of the line.
Now, use the point-slope formula to create an equation, where
is the slope and
is a known point on the line. ![y-y_1=m(x-x_1)](https://tex.z-dn.net/?f=y-y_1%3Dm%28x-x_1%29)
Substitute the values. ![y-3=-2(x-0)](https://tex.z-dn.net/?f=y-3%3D-2%28x-0%29)
Simplify. ![y-3=-2x](https://tex.z-dn.net/?f=y-3%3D-2x)
Move the
to create the final equation in slope-intercept form. ![\large\boxed{y=-2x+3}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7By%3D-2x%2B3%7D)