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3 years ago

In a study, the sample is chosen by pulling 50 names from a hat What is the sampling method?

Mathematics

1 answer:

Irina18 [472]3 years ago

6 0

Answer:Simple random sample

Step-by-step explanation:

A simple random sample is a subset of a statistical population in which each member of the subset has an equal probability of being chosen. A simple random sample is meant to be an unbiased representation of a group.

NOTE:

No easier method exists to extract a research sample from a larger population than simple random sampling. Selecting subjects completely at random from the larger population also yields a sample that is representative of the group being studied.

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Please answer this math question for me

vampirchik [111]

Answer:

D=90° E=103° F=77°

Step-by-step explanation:

D+90°=180°

D=90°

F+103°=180°

F=77°

E + F=180°

E=103°

6 0

3 years ago

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Please help me with this sum

dimulka [17.4K]

Answer:

3950÷5=790 (790×5=3950)

1914÷6=319 (319×6=1914)

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2 years ago

Which of the following equations is equivalent to 3(a - 5) = 4a ?

Nikitich [7]

Answer:

2a = 15- a ..................

5 0

3 years ago

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One technique of killing cancer cells involves inserting microscopic synthetic rods, called carbon nanotubules, into the cell. W

Vlad [161]

Answer:

The probability that the cell will be killed is 0.9328.

Step-by-step explanation:

We are given that five nanotubules are inserted in a single cancer cell. Independently of each other, they become exposed to near-infrared light with probabilities 0.2, 0.4, 0.3, 0.6, and 0.5.

Let the event that a cell is killed be 'A' and the event where the ith nanotubule kill the cell be ' $\text{B}_i$ '.

This means that the cell will get killed if $\text{B}_1 \bigcup \text{B}_2 \bigcup \text{B}_3 \bigcup \text{B}_4 \bigcup \text{B}_5$ happens. This represents that the cell is killed if nanotubule 1 kills the cell, or nanotubule 2 kills the cell, and so on.

Here, P( $\text{B}_1$ ) = 0.2, P( $\text{B}_2$ ) = 0.4, P( $\text{B}_3$ ) = 0.3, P( $\text{B}_4$ ) = 0.6, P( $\text{B}_5$ ) = 0.5.

So, the probability that the cell will be killed is given by;

P(A)= $1 - [(1 - P(\text{B}_1)) \times (1 - P(\text{B}_2)) \times (1 - P(\text{B}_3)) \times (1 - P(\text{B}_4)) \times (1 - P(\text{B}_5))]$

P(A) = $1 - [(1 - 0.2) \times (1 - 0.4) \times (1 - 0.3) \times (1 - 0.6) \times (1 - 0.5)]$

P(A) = $1 - (0.8 \times 0.6 \times 0.7 \times 0.4 \times 0.5)$

P(A) = 1 - 0.0672 = 0.9328

Hence, the probability that the cell will be killed is 0.9328.

4 0

4 years ago

The curve y = |x|/ 5 − x2 is called a bullet-nose curve. find an equation of the tangent line to this curve at the point (2, 2).

diamong [38]

We have the following curve:

$y=\frac{\left | x \right |}{5-x^2}$

So we need to find an equation of the tangent line to this curve at the point $(2,2)$ . So let's find out if this point, in fact, belongs to the curve:

 $If \ x=2 \\ \\ y=\frac{\left | 2 \right |}{5-2^2}=\frac{\left | 2 \right |}{5-4}=2$ .

We also know that:

 $\left | x \right |= \left \{ {{x \ if \ x \ \geq 0} \atop {-x \ if \ x\ \textless \ 0}} \right.$ 

Given that the point is:

 $(2,2)\ that \ is: \\ x=2\ \textgreater \ 0$

Then we will say that:

$\left | x \right |=x$

Therefore:

$y=\frac{x}{5-x^2}$

Computing the derivative:

$y=\frac{x}{5-x^2} \\ \frac{dy}{dx}= \frac{(1)(5-x^2)-(-2x)x}{(5-x^2)^2}=\frac{5+x^2}{(5-x^2)^2}$

So the derivative solved for $x=2$ is in fact the slope of the line at the point $(2,2)$ , then:

$\frac{dy}{dx} |_{x=2}=\frac{5+x^2}{(5-x^2)^2}|_{x=2}=\frac{5+2^2}{(5-2^2)^2}=9 \\ \\ \therefore m=\frac{dy}{dx} |_{x=2}=9$

Finally, the tangent line is:

$y-y_1=m(x-x_1) \\ \therefore y-2=9(x-2) \\ \therefore \boxed{y=9x-16}$

This is shown in the figure below.

8 0

3 years ago