Question

Assume you have sea water that weighs 64 lb/ft³ and contains 35 parts per thousand (0.0035) dissolved salt by weight. How many cubic feet of the sea water would you need to place in an exaporation basin to collect 125 lb of sea salt?

Answer 1

Answer:

558.036 lb

Step-by-step explanation:

Let x is the amount of the sea water to collect 125 lb of sea salt

As given: 64 lb/ft³ has 0.0035 dissolved salt by weight

So the formula to find out the amount of the sea water is:

64 lb/ft³ * 0.0035 *x ft³  = 125 lb

<=> x = $\frac{125}{64*0.035}$ = 558.036 lb

Hope it will find you well.