Answer:
Yuri is not correct.
Step-by-step explanation:
Given expression is q(x) = 6x³ + 19x² - 15x - 28
If 'a' is a root of the given function, then by substituting x = a in the expression, q(a) = 0
Similarly, for x = 
,
= 
= 
= 
= 
= 
≠ 0
Therefore, Yuri is not correct. x = can not be a root of the given expression.
3 of anything positive is greater than 2 of the same thing.
I can't think of an exception.
F(x) =16ˣ and g(x) = 16⁽ˣ/₂⁾
Since 16 = 2⁴, then we can write:
f(x) =2⁽⁴ˣ⁾ and g(x) = 2⁽⁴ˣ/₂⁾ = 2²ˣ
for x = 1 f(x) = 2⁴ = 16
for x = 1 g(x) = 2² = 4
(√16 = 4)
for x = 2 f(x) = 2⁸ = 256
for x = 2 g(x) = 2⁴ =16
(√256) = 16
for x = 3 f(x) = 2¹² = 4096
for x = 1 g(x) = 2⁶ = 64
(√4096 = 64)
We notice that:
The output values of g(x) are the square root of the output values of f(x) for the same value of x.
I thinks is A or B if not I’m sorry
