Question

Find dy/dx and d2y/dx2, and find the slope and concavity (if possible) at the given value of the parameter. (If an answer does not exist, enter DNE.) Parametric Equations Point x = 6t, y = 4t − 3 t = 4

Answer 1

Answer:

The slope of the function is  ²/₃ and since the second derivative is zero, the concavity doesn't exist.

Step-by-step explanation:

Given;

x = 6t

y = 4t - 3

point t = 4

$\frac{dy}{dx} = (\frac{dy}{dt} )/(\frac{dx}{dt} )=\frac{\frac{dy}{dt} }{\frac{dx}{dt}} \\\\\frac{dy}{dt} = 4; \frac{dx}{dt} = 6\\\\\frac{dy}{dx} =\frac{4}{6} = \frac{2}{3}$

The slope of the function is  ²/₃

take the second derivative of the function;

the second derivative will be zero since the first derivative is a constant value.

$\frac{d^2y}{dx^2} = 0$

Since the second derivative is zero, the concavity doesn't exist.