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2 years ago

Item 7 Complete the statement. Round to the nearest hundredth if necessary. 64 lb ≈ kg

Mathematics

1 answer:

Marina CMI [18]2 years ago

7 0

Answer:

64 lb = 29.029912 kg

Rounded to the nearest hundredth is 29.03 kg

hope this helps!

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Can somebody solve this?

balandron [24]

Answer:

y = − 4 +2x/3

Step-by-step explanation:

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2 years ago

Tim's taxicab business charges a fixed dollar amount to pick up passengers, plus a per-mile charge. The fixed cost, y, given as

MissTica

In y = 2x + 3, 3 represents the fixed cost and 2 represents the cost-per-mile.

The per mile charnge, in dollars per mile, is $2/mile (answer)

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3 years ago

15 total kids were at the park. 6 of them were girls. What % of the kids were girls?

Vikentia [17]

Answer:

40%

Step-by-step explanation:

6/15 = 0.4

0.4 * 100 = 40%

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2 years ago

Read 2 more answers

Complete the equation, by supplying the missing exponent.<br> m•n2•m3= m 11n2

MaRussiya [10]

Given:

Consider the given equation is:

$m^?\cdot n^2\cdot m^3=m^{11}\cdot n^2$

To find:

The missing exponent.

Solution:

Let x be the missing exponent. Then the given equation can be written as

$m^x\cdot n^2\cdot m^3=m^{11}\cdot n^2$

It can be rewritten as:

$(m^x\cdot m^3)\cdot n^2=m^{11}\cdot n^2$

$m^{x+3}\cdot n^2=m^{11}\cdot n^2$ $[\because a^ma^n=a^{m+n}]$

On comparing the coefficient of m, we get

$x+3=11$

$x=11-3$

$x=8$

Therefore, the value of the missing exponent is 8. So, the complete equation is $m^8\cdot n^2\cdot m^3=m^{11}\cdot n^2$ .

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2 years ago

The engine torque y (in foot-pounds) of one model of car is given by y=−3.75x2+23.2x+38.8, where x is the speed (in thousands of

Stels [109]

Answer:

Step-by-step explanation:

If the engine torque y (in foot-pounds) of one model of car is given by y=−3.75x^2+23.2x+38.8

The engine speed is at maximum if dy/dx = 0

dy/dx = -2(3.75)x+23.2

dy/dx = -7.5x + 23.2

since dy/dx = 0

0 = -7.5x + 23.2

7.5x = 23.2

x = 23.2/7.5

x = 3.093

Hence the maximum torque is 3.09 rev/min

8 0

2 years ago