Answer:
1.) 48
2.) 65
3.) 36
Step-by-step explanation:
1.) If the equation is 6(x-4) and x = 12, then all we have to do is plug in the value of x. When we plug in, all we do is substitute 12 for x because they mentioned in the question that x = 12. So, we end up getting 6(12 - 4). After solving this, we get 48.
2.) This problem is a lot like the last problem. All we need to do is substitute /plug in the values of x and y into the equation, to get 4(4^2) - 35/7 - (8 + 14). After solving, we get 65.
3.) . This problem, once again, is also a lot like the last problems. We need to substitute the value of x into the equation 8x+12. Since we know from the problem that x is 3, all we have to do is 8 * 3 + 12.
Distance = r x t ===> t=d/r
Distance (after 2 hours driving @30mil/hr) = 2 x 30 = 60 Mil
To drive same distance (60) with r = 50, the time needed is 60/50 =1.2 hrs
Answer:
hey i think you forgot to add the expression, would u mind adding the question :) thanks
Step-by-step explanation:
The GCF of 30, 48, and 60 is 6.
Answer:
c
you subtract the exponents when dividing numbers with the same base
