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geniusboy [140]
3 years ago
9

How to simplify the square root of 126

Mathematics
1 answer:
Neporo4naja [7]3 years ago
4 0
\sqrt{126} =  \sqrt{9 \times 14} =  \sqrt{9} \times  \sqrt{14} = 3 \sqrt{14}

3 \sqrt{14} is the final answer :)
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Write a rule for the nth term of the geometric sequence for which a1=−6 and a5=−486
patriot [66]

The geometric rule for the nth term of the geometric sequence for which a1 =−6 and a5=−486 is -6 × 3^(n - 1)

<h3>The nth term of a geometric sequence</h3>

First term, a1 = -6

Fifth term, a5 = -486

a5 = ar^(n - 1)

-486 = -6 × r^(5-1)

-486 = -6r⁴

r⁴ = -486 / 6

r⁴ = 81

r = 4√81

r = 3

Geometric rule:

nth term = ar^(n-1)

nth term = -6 × 3^(n - 1)

Learn more about geometric sequence:

brainly.com/question/24643676

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