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arlik [135]
3 years ago
12

A quarterback is standing in the middle of the field 60 yards from his goal line. He passes the ball to a player 12 yards to his

left on the 55 yard line. How long was the pass?
Mathematics
1 answer:
Minchanka [31]3 years ago
4 0
It will be 103 because 60 he passed the ball so you will take away 12 and he must've caught it so add 55 then it will be 103 hope I helped
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Erika calculated that she would spend $115 on school supplies this year. She actually spent $82.50 on school supplies. What is E
DerKrebs [107]
The equation to find percent error is:
percent error=(experimental-theoretical)/theoretical *100
So, (115-82.5)/82.5=0.393939*100
39.3939%, or 39.94%

Hope this helps!!
6 0
3 years ago
Read 2 more answers
Marcy wants $205 in her bank account. If she has $85 now and adds $10 per week, how many weeks will it take her to reach her goa
DIA [1.3K]

Answer:

^^1 week and 5 days

Explanation:

If she has $85 now, and gains $10 per week, by the next week and 5 days, she should have her goal of $205. Hope it helps!

5 0
3 years ago
Jerome will also order t-shirt for the volunteers he will order both adults and child size t shirt
RideAnS [48]

a >= 200

5 a + 2.5 c <=1500

Step-by-step explanation:

Step 1 :

Let c be the number of child t shirt and a be the number of adult t-shirts

Given the cost of adult t-shirt is $5 and the cost of child t-shirt is $2.50

Step 2 :

Inequality 1

Given that Jerome needs at least 200 adult t-shirts .

So the minimum quantity of adult t-shirts should be 200

Hence we have a >= 200

Step 3 :

Inequality 2

Given that the total cost should be less that $1500

We have,

5 a + 2.5 c <=1500

5 0
3 years ago
Read 2 more answers
What does x equal (x/4)+12=38
user100 [1]
\frac{x}{4} +12=38\\\\ \frac{x}{4}=26\\\\x=104
8 0
3 years ago
Read 2 more answers
The t value for a 99% confidence interval estimation based upon a sample of size 10 is
Aliun [14]
Answer:
For a sample size of 10, the t-value is about 3.25 (from tables) at a 99% confidence interval.

Explanation:
When the standard deviation for the population is not known, the confidence interval estimate for the population mean is performed with the Student's t-distribution.
The confidence interval for the mean is calculated as
(\Bar{x}- t\frac{s}{\sqrt{n}} , \, \Bar{x}+ t\frac{s}{\sqrt{n}}
where
 \Bar{x} = sample mean,
s = sample standard deviation,
t = t-value (provided in tables),
n =  sample size.

When reading the t-value, (n-1) is called the df or degrees of freedom.

7 0
3 years ago
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