Answer:
Step-by-step explanation:
We know that a rational number cannot have roots. All of the answer choices cannot be simplified except for , which can become 1. Therefore, our answer is
.
If I got a 28% on a test and my grade is an 88% he would that affect my grade?
2 answers:
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We are given the equations 3x+5y=-3 and x-5y=-5.
Both equations have a 5y term which allows us to easily solve the system by elimination. To do so we will add the equations together like a simple addition problem by adding the x terms together, the y terms together, and the integer answers together.
3x + 5y = -3
+x - 5y = -5
---------------
4x + 0y = -8
The y terms cancel out since one is positive and one is negative. Now we can solve for x.
4x = -8
x = -2
Now plug -2 in for x in one of the original equations to find y.
(-2) - 5y = -5
-5y = -3
y = 3/5
Our answer as an ordered pair is (2, 3/5)
Both equations have a 5y term which allows us to easily solve the system by elimination. To do so we will add the equations together like a simple addition problem by adding the x terms together, the y terms together, and the integer answers together.
3x + 5y = -3
+x - 5y = -5
---------------
4x + 0y = -8
The y terms cancel out since one is positive and one is negative. Now we can solve for x.
4x = -8
x = -2
Now plug -2 in for x in one of the original equations to find y.
(-2) - 5y = -5
-5y = -3
y = 3/5
Our answer as an ordered pair is (2, 3/5)
Answer:
g(x)<j(x)<k(x)<f(x)<m(x)<h(x)
Step-by-step explanation:
1.
The denominator of f is defined for all real values of x
Therefore, the function is continuous on the set of real numbers
3.
It cannot be factorize .
Therefore, it has no real values for which it is not defined .
Hence, function h is defined for all real values.
2.
The denominator of g is defined for all real values of x.
Therefore, the function g is continuous on the set of real numbers
4.
x-9=0
x=9
The function i is not defined for x=9
Therefore, the function i is not continuous on the set of real numbers.
5.
The denominator of j is defined for all real values of x.
Therefore, the function j is continuous on the set of real numbers.
6.
It cannot be factorize .
Therefore, it has no real values for which it is not defined .
Hence, function k is defined for all real values.
7.
The function is not defined for x=8 and x=1
Hence, function l is not defined for all real values.
8.
The denominator of m is defined for all real values of x.
Therefore, the function m is continuous on the set of real numbers.
g(x)<j(x)<k(x)<f(x)<m(x)<h(x)