Can anyone say me the answer from 4 d
1 answer:
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For this case we must solve the following equation:
We apply distributive property on the right side of the equation:
We subtract 6y on both sides of the equation:
We subtract 6 from both sides of the equation:
Dividing by 6 on both sides of the equation:
So, the result is
Answer:
Answer:
Step-by-step explanation:
Hello!
The research team created a cracker with fewer calories. The average content of calories of the new crackers per serving of 6 should be less than 60.
To test it a random sample of 26 samples of the new cracker was taken and the calories per serving were measured.
Then the study variable is
X: calories of a 6 serve sample of the new reduced-calorie version. (cal)
The variable has a normal distribution with a population standard deviation of 0.82 cal.
To test the claim that the new crackers have on average less than 60 calories, the parameter of interest is the population mean (μ) and the hypotheses are:
H₀: μ ≥ 60
H₁: μ < 60
α: 0.01
Since the variable has a normal distribution and the population variance is known, the best statistic to use to conduct the test is a Standard Normal
This test is one tailed to the left, wich means that the null hypothesis will be rejected at low levels of the statistic.
If Z ≤ -2.334, the decision is to reject the null hypothesis.
If Z > -2.334, the decision is to not reject the null hypothesis.
Using the data of the sample I've calculated the sample mean.
X[bar]= ∑X/n= 1548.61/26= 59.56 cal
The observed Z value is less than the critical value, so the decision is to reject the null hypothesis.
At a level of significance of 1%, you can conclude that the population mean of calories of the samples of new crackers is less than 60 cal.
I hope it helps!
Answer:
Step-by-step explanation:
Slope-intercept form of a <u>linear equation</u>:
where:
- m is the slope.
- b is the y-intercept (where the line crosses the y-axis).
<u>Slope formula</u>
<u>Equation 1</u>
<u />
Define two points on the line:
<u>Substitute</u> the defined points into the slope formula:
From inspection of the graph, the line crosses the y-axis at y = 1 and so the y-intercept is 1.
Substitute the found slope and y-intercept into the slope-intercept formula to create an equation for the line:
<u>Equation 2</u>
<u />
Define two points on the line:
<u>Substitute</u> the defined points into the slope formula:
From inspection of the graph, the line crosses the y-axis at y = -4 and so the y-intercept is -4.
Substitute the found slope and y-intercept into the slope-intercept formula to create an equation for the line:
<u>Conclusion</u>
Therefore, the system of linear equations shown by the graph is:
Learn more about systems of linear equations here: