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3 years ago

10

Josie is getting her hair cut and styled. She wants to give a 20% tip to her stylist. If the haircut costs $15.00, how much tip

should she give

1 answer:

o-na [289]3 years ago

8 0

$15.00 * 20% = $15.00 * 0.2 = $3.<span>00
the answer is </span>$3.<span>00</span>

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To make one ham sandwich, tina uses one bread roll and two ham slices

igor_vitrenko [27]

Answer:

£67.78

Step-by-step explanation:

Bread - 6 x £2.87 = £17.22

Ham - 8 x £6.32 = £50.56

£17.22

+ <u>£50.56</u>

£67.78

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3 years ago

Ron made 3 pitchers of lemonade to sell at a lemonade stand. The cost of making the lemonade is 50 cents per pitcher of lemonade

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2 years ago

sandy is having a thanksgiving feast for her family of 24. she is deciding between these two options. Help please which one is b

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2 years ago

What property is -6+24=x-24+24

Ipatiy [6.2K]

Answer:

x = 30

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2 years ago

student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te

alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = $\frac{1}{4}$ .

Thus, the probability that the student does not receive version A = $1-\frac{1}{4}$ = $\frac{3}{4}$ .

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

$\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}$

= $(\frac{1}{4})^3\times (\frac{3}{4})^2+(\frac{1}{4})^4\times (\frac{3}{4})+(\frac{1}{4})^5$

= $(\frac{1}{4})^3\times (\frac{3}{4})[\frac{3}{4}+\frac{1}{4}+(\frac{1}{4})^2]$

= $(\frac{3}{4^4})[1+\frac{1}{16}]$

= $(\frac{3}{256})[\frac{17}{16}]$

= 0.01171875 × 1.0625

= 0.01245

Thus, the probability that at least 3 out of 5 students receive version A is 0.0124

So, in percent the probability is 0.0124 × 100 = 1.24%

To the nearest tenth, the required probability is 1.2%.

4 0

3 years ago