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lana66690 [7]
3 years ago
15

a tree casts a shadow 32 feet long .the Angle of elevation of the sun is 62° what is the height of the tree

Mathematics
2 answers:
RoseWind [281]3 years ago
5 0
90-62= 28
law of sines 28/32= sin 62/h
h= 32 sin 62/sin 28
h= 60.18 feet
Delicious77 [7]3 years ago
4 0
\tan \theta = \dfrac{opp}{adj}

\tan 62^\circ = \dfrac{y}{32~ft}

y = 32 \tan 62^\circ ~ft

y = 60.2 ~ft

Answer: The tree is 60.2 ft tall.
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Two sides of a triangle measure 27 inches and 32 inches. Which could represent the length of the third side?
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Answer:

Step-by-step explanation:

The third side could have dimension x

32 - 27 < x < 32 + 27

         5 < x < 59

There are a few special triangles

Equilateral triangle could have legs

27, 32, <u>27</u>

or

32, 27,<u> 32</u>

A right triangle could have the third side

√(27² + 32²) = <u>√1753</u> which is about<u> 41.87</u>

or

√(32² - 27²) = <u>√295</u> which is about <u>17.18</u>

Notice all these fit within the original limits specified.

3 0
2 years ago
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THe answer to the question is 32 or 28
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3 years ago
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If AB is 12, what is the length of A'B'?
lukranit [14]

Triangles ABC and A'B'C are similar. This means that the corresponding sides are in the same ratio, in this case:

\frac{BC}{B^{\prime}C}=\frac{AC}{A^{\prime}C}=\frac{AB}{A^{\prime}B^{\prime}}

Replacing with data:

\begin{gathered} \frac{9}{6}=\frac{12}{A^{\prime}B^{\prime}} \\ 9\cdot A^{\prime}B^{\prime}=12\cdot6 \\ A^{\prime}B^{\prime}=\frac{72}{9} \\ A^{\prime}B^{\prime}=8 \end{gathered}

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Let $r$ and $s$ be the roots of $3x^2 + 4x + 12 = 0.$ Find $r^2 + s^2.$ Pls help.
nirvana33 [79]

Answer:

-56/9

Step-by-step explanation:

By Vieta's formulas,

$r + s = -\frac{4}{3}$ and $rs = \frac{12}{3} = 4.$ Squaring the equation $r + s = -\frac{4}{3},$ we get

$r^2 + 2rs + s^2 = \frac{16}{9}.$ Therefore,

$r^2 + s^2 = \frac{16}{9} - 2rs = \frac{16}{9} - 2 \cdot 4 = -\frac{56}{9}}$

5 0
3 years ago
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