Answer:
(-2, -8)
x = -2
y = -8
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define systems</u>
13x - 6y = 22
x = y + 6
<u>Step 2: Solve for </u><em><u>y</u></em>
<em>Substitution</em>
- Substitute in <em>x</em>: 13(y + 6) - 6y = 22
- Distribute 13: 13y + 78 - 6y = 22
- Combine like terms: 7y + 78 = 22
- Isolate <em>y</em> term: 7y = -56
- Isolate <em>y</em>: y = -8
<u>Step 3: Solve for </u><em><u>x</u></em>
- Define original equation: x = y + 6
- Substitute in <em>y</em>: x = -8 + 6
- Add: x = -2
Five dimes and one quarter = .75.
9.75/.75=3.25*4/1=13
there are 13 "5 dimes and 1 quarter"s
so 65 dimes
Answer:
a) 23.5619449 m^2 b) 351.8583772 cm^2 c) 75.39822369 cm^2
Step-by-step explanation:
a):
SA = 2πr^2+2πr
r= 3/2 = 1.5
SA= 2π*1.5^2 + 2π*1.5
SA= 15/2 ∏
SA= 23.5619449 m^2 round it as you want
b): Same steps as "a" but rather than m^2 it is cm^2
the answer will be:
SA= 112π
SA= 351.8583772 cm^2 round it as you want
c): the radius is already given so just place it in place of r
SA= 2π*3^2 + 2π*3
SA= 24π
SA= 75.39822369 cm^2
hello my name is bobert anyone of you students who have $ex with me shall win dez nuts now gimme them points
