A line passes through (6,3), (8,4), and (n,-2). Find the value of n.
2 answers:
If a line pass through three points, they are collinear points, and the determinant of a matrix produced by their coordinates equals 0.
Knowing this, we can fin the value of n.
We need a triangular matrix, so we can complete it with 1's.
![\left[\begin{array}{ccc}6&3&1\\8&4&1\\n&-2&1\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%263%261%5C%5C8%264%261%5C%5Cn%26-2%261%5Cend%7Barray%7D%5Cright%5D%20)
24 + 3n - 16 - 4n + 12 - 24 = 0
- n - 4 = 0
- n = 4
n = -4
The value of n it's -4.
Hope it helps.
Knowing this, we can fin the value of n.
We need a triangular matrix, so we can complete it with 1's.
24 + 3n - 16 - 4n + 12 - 24 = 0
- n - 4 = 0
- n = 4
n = -4
The value of n it's -4.
Hope it helps.
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The speed of plane 1 will be 300 miles/sec and that of plane 2 will be 600 miles/sec.
We have two planes flying in opposite directions to each other.
We have to determine how fast was the each plane flying.
<h3>What is the formula to calculate the distance covered by the object moving with speed - x m/s in time - t s ?</h3>The formula to calculate the distance travelled will be -
distance = speed x time = (t) meters
According to the question -
Let us assume that the speed of plane 1 = v miles/sec.
Then, the speed of plane 2 will be = 2v miles/sec.
Distance covered by plane 1 in 3 hours will be = 3v miles.
Distance covered by plane 2 in 3 hours will be = 3 x (2v) miles = 6v miles.
Since they are 2700 miles apart after three hours, therefore -
3v + 6v = 2700
9v = 2700
v = 300 miles/sec
Hence, the speed of plane 1 will be 300 miles/sec and that of plane 2 will be = 2v = 2 x 300 = 600 miles/sec.
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